Answer:
5.03 m/s
Explanation:
Give
Speed = v = 24m/s
Wavelength = λ = 30cm = 0.3m
Amplitude = A = 1.0cm = 0.01m
The velocity of a point in Simple Harmonic Motion
at any time t is given by the following formula
v = ωA cos ωt
The value is the Maximum when cosωt.
The maximum value of cosωt. is 1.
Hence the maximum velocity is ωA
Velocity of the wave v=n λ
n = v/ λ = 24 /0.3 = 80
ω = 2πn = 2π*80 = 502.86 rad/s
Maximum velocity of the particle is
ωA = 502.86 * 0.01 = 5.03m/s
Answer:
a) 5 m from the finish line
b) 4875 s
Explanation:
distance = 1 km
tortoise speed = 0.2 m/s
speed of hare = 8 m/s
time take by hare t reach 0.8 km =
time taken by tortoise to travel 1 km =
time taken by the hare to travel 0.2 km =
time taken by the tortoise to travel 0.2 km =
distance traveled by tortoise in 25 second = 25 × 0.2 = 5 m
a) when tortoise is 5 m from the finish line then hare will resume the race.
b) the hare will be stationary for = 5000 - 125 = 4875 s
Answer:
The minimum angular speed 57.0 rad/s
Explanation:
In this exercise we must use the relationships between the angular and linear magnitudes, for the speeds we have
v = w r
As they give us that linear velocity is constant, we will calculate the angular velocity for the two radii, external and internal
r1 = 11.75 cm (1 m / 100cm) = 0.1175 m
w1 = v / r1
w1 = 6.70 / 0.1175
w1 = 57.0 rd / s
R2 = 4.50 cm = 0.0450 m
w2 = 6.70 / 0.0450
w2 = 148 rad / s
The minimum angular speed 57.0 rad / s
Answer: it shows T- Storms
Explanation:
i looked it up
Work = force x distance
So 88x15 = work
1,320N/m = work