Answer:
E = 10t^2e^-10t Joules
Explanation:
Given that the current through a 0.2-H inductor is i(t) = 10te–5t A.
The energy E stored in the inductor can be expressed as
E = 1/2Ll^2
Substitutes the inductor L and the current I into the formula
E = 1/2 × 0.2 × ( 10te^-5t )^2
E = 0.1 × 100t^2e^-10t
E = 10t^2e^-10t Joules
Therefore, the energy stored in the inductor is 10t^2e^-10t Joules
Answer:
The object would weight 63 N on the Earth surface
Explanation:
We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:
Now, if the body is on the surface of the Earth, its weight (w) would be:
Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:
Answer:
In marine ecosystems, climate change is associated with concurrent shifts in temperature, circulation, stratification, nutrient input, oxygen content, and ocean acidification. There are also strong linkages between climate and species distributions, phenology, and demography.
Explanation:
Mark her brainliest
Random variable
Explanation:
A function that assigns a numerical value to each outcome of an experiment is described as a random variable. Random variables helps to determine the outcome of a random event.
- Example of a random event is tossing of die, casting of a coin.
- Random variables ascribe numerical values to the outcome of an experiment.
- They are often used in probability to determine the extent of the certainty of an experimental procedure.
Learn more:
Probability brainly.com/question/1637111
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