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svetlana [45]
3 years ago
15

Sally Sizzle builds a circuit by connecting three resistors in parallel with a 9V battery. The current in this circuit is 3.6 am

ps. Sally wants to add another resistor in parallel to increase the current to 4.6 amps. What should the resistance of this new resistor be? A) 0.5 Ohms B) 5 Ohms C) 9 Ohms D) 10 Ohm
Physics
2 answers:
Andru [333]3 years ago
7 0

Then answer is C 9 ohms

kodGreya [7K]3 years ago
7 0

Answer:

C) 9 Ohms

Explanation:

Initially, the voltage in the circuit is V = 9 V and the current is I = 3.6 A, with three resistors connected in parallel. We can calculate the initial equivalent resistance of the circuit by using Ohm's law:

R_T = \frac{V}{I}=\frac{9 V}{3.6 A}=2.5 \Omega

Now Sally wants to add another resistor in parallel to increase the total current to I = 4.6 A. Since the new resistor is added in parallel, the new equivalent resistance will be:

\frac{1}{R_T'}=\frac{1}{R_T}+\frac{1}{R_{new}} (1)

where R_{new} is the new resistor that should be added.

Again, we can calculate the new equivalent resistance by using Ohm's law:

R_T' = \frac{V}{I}=\frac{9 V}{4.6 A}=1.96 \Omega

And substituting this value into eq.(1), we find the value of R_{new}:

\frac{1}{R_{new}}=\frac{1}{R_T'}-\frac{1}{R_T}=\frac{1}{1.96 \Omega}-\frac{1}{2.5 \Omega}=0.110 \Omega^{-1}\\R_{new}=\frac{1}{0.110}=9 \Omega

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Answer:

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In this way, we establish the equation for the principle of conservation and energy.

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E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.

W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]

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Answer:

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The initial velocity is 5 m/s

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Acceleration = Change in speed ÷ time

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