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3 years ago

Predict what the MASS would be of something exerting a force of 45N on a spring scale. EXPLAIN how you got

1 answer:

8 0

The mutual forces of gravity between the Earth and an object on or near
its surface are (mass of the object) x (acceleration of gravity on Earth).
These two forces are equal, and we call their strength the "weight" of
the object. It's the number shown on the scale as long as nobody has
their thumb on the scale. In this problem, the force is 45N . (That's
about 10.12 pounds.)

The acceleration of gravity on Earth is about 9.8 meters per second² .

So 45N = (mass in kilograms) x (9.8 meters per second²)

Divide each side by 9.8 : Mass = 45/9.8 = 4.59 kilograms (rounded)

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A 0.45kg baseball is pitched towards home plate at 20 m/s. The ball is hit back towards the pitcher with a speed of 30 m/s. What

Inessa05 [86]

Answer:

4.5kgm/s

Explanation:

Change in momentum is expressed as

Change in momentum = m(v-u)

M is the mass

V is the final velocity

u is the initial velocity

Given

m=0.45kg

v = 30m/s

u = 20m/s

Substitute

Change in momentum = 0.45(30-20)

Change in momentum = 0.45×10

Change in momentum = 4.5kgm/s

3 0

2 years ago

Question Part Points Submissions Used A car is stopped for a traffic signal. When the light turns green, the car accelerates, in

olya-2409 [2.1K]

(a) 328.6 kg m/s

The linear impulse experienced by the passenger in the car is equal to the change in momentum of the passenger:

$I=\Delta p = m\Delta v$

where

m = 62.0 kg is the mass of the passenger

$\Delta v$ is the change in velocity of the car (and the passenger), which is

$\Delta v = 5.30 m/s - 0 = 5.30 m/s$

So, the linear impulse experienced by the passenger is

$I=(62.0 kg)(5.30 m/s)=328.6 kg m/s$

(b) 404.7 N

The linear impulse experienced by the passenger is also equal to the product between the average force and the time interval:

$I=F \Delta t$

where in this case

$I=328.6 kg m/s$ is the linear impulse

$\Delta t = 0.812 s$ is the time during which the force is applied

Solving the equation for F, we find the magnitude of the average force experienced by the passenger:

$F=\frac{I}{\Delta t}=\frac{328.6 kg m/s}{0.812 s}=404.7 N$

7 0

3 years ago

Which of these forces determines the chemical properties of an atom? friction force nuclear force gravitational force electrical

zysi [14]

The answers is an electrical force.
Under normal conditions, atoms interact with each other via electrons that are furthest away from the nucleus. These electrons from the what is called the outer shell of the atom, electrons from the outer shell that can participate in chemical reactions are called valence electrons.

3 0

3 years ago

The dot or scalar product of two (3d) vec- tors ⃗a = ⟨a1,a2,a3⟩ and ⃗b = ⟨b1,b2,b3⟩ is defined as

Neko [114]

Yes, yes, we know all of that. It certainly took you long enough to
get around to asking your question.

If
   a = (14, 10.5, 0)
and
   b = (4.62, 9.45, 0) ,

then, to begin with, neither vector has a z-component, and they
both lie in the x-y plane.

Their dot-product a · b = (14 x 4.62) + (10.5 x 9.45) =

         (64.68)   +   (99.225) = 163.905 (scalar)

I feel I earned your generous 5 points just reading your treatise and
finding your question (in the last line). I shall cherish every one of them.

7 0

3 years ago

Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not?

Mariulka [41]

Answer:

Yes

Explanation:

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is the velocity of the object

We know that an elephant has a mass much larger than the mass of an ant. However, we see that the momentum of the animal also depends on its velocity.

If the elephant is at rest, its velocity is zero:

v = 0

so its momentum is also zero:

p = 0

And therefore, an ant which is moving (so, non-zero speed) can have more momentum than an elephant, if the elephant is at rest.

6 0

2 years ago