Question

If an object is projected upward with an initial velocity of 127 ft per? sec, its height h after t seconds is h equals negative 16 t squared plus 127 th=?16t2+127t. find the height of the object after 55 seconds.

Answer 1

To determine the height of the object given the time, we simply use the given relation between height and time in the problem statement. It is given as:

h = -16t^2 + 127t

We substitute 55 seconds to t and obtain,

h = -16(55)^2 + 127(55)
h = - 41415