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Licemer1 [7]
3 years ago
8

An inductor has an inductance of 0.12 mH. Calculate the number of turns per unit length of this inductor if it has a total of 50

0 turns in it. The cross-sectional area of the solenoid is 2.00 cm^2. Take μo = 4πx10^-7 m/A.
Physics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

oh                      

Explanation:

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1. What is the average velocity of a car that moved 40 km East and 80 km West in 2 hours?
irina [24]

The average velocity is 20 km/h west

Explanation:

The velocity of an object is given by:

velocity = \frac{d}{t}

where

d is the displacement

t is the time elapsed

The displacement of an object is a vector connecting the initial position and the final position of motion.

In this problem, the car moved

40 km East

80 km West

Therefore, the displacement is given by (taking West as positive direction)

d=80 km - 40 km = 40 km West

The time elapsed is

t = 2 h

Therefore, the average velocity is

v=\frac{40 km}{2h}=20 km/h in the West direction.

Learn more about average velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

7 0
3 years ago
An object experiences an acceleration of 8.5 m/s^2 over a distance of 300 m. After that acceleration it has a velocity of 400 m/
Snezhnost [94]

Answer:

393.6m/s

Explanation:

Given parameters:

Acceleration  = 8.5m/s²

Distance  = 300m

Final velocity  = 400m/s

Unknown:

Initial velocity  = ?

Solution:

To solve this problem, we use the expression below;

             v² = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

      So;

               v²  - 2as = u²

        u²   = v²   - 2as

        u²  = 400²   - (2 x 8.5 x 300)  

         u   = 393.6m/s

7 0
3 years ago
Read 2 more answers
When the three primary pigments are mixed , the resulting is
azamat
You would end up with a brown/black color depending on how much of each pigment was added! Hope this helps.
6 0
3 years ago
A small button placed on a horizontal rotating platform with diameter 0.520 m will revolve with the platform when it is brought
yawa3891 [41]

For the position of button we can use force balance as

Friction Force = Centripetal force

so here we will have

\mu_s mg = m\omega^2 R

here we know that

R = radius of circle where button is placed

\omega = 2\pi f

f = 35 rev/min

f = \frac{35}{60} rev/s = 0.58 rev/s

\omega = 2\pi (0.58) = 3.66 rad/s

now from above equation

\mu_s(m)(9.81) = (3.66)^2(0.240)

\mu_s = 0.33

so friction coefficient will be 0.33

5 0
4 years ago
A ladder of length 10 is leaning against a wall. The vertical wall is frictionless while the horizontal surface is rough. The an
bogdanovich [222]

Answer:

105.1N

Explanation:

According to the newton second law

\sum F_x = ma_x\\F_m - F_f = ma_x\\

Since the acceleration is zero, then;

F_m - F_f = 0\\Fm = F_f\\

Since;

F_m = mg sin \theta, \  hence \ F_f = mg sin \theta

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

8 0
3 years ago
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