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Licemer1 [7]
2 years ago
8

An inductor has an inductance of 0.12 mH. Calculate the number of turns per unit length of this inductor if it has a total of 50

0 turns in it. The cross-sectional area of the solenoid is 2.00 cm^2. Take μo = 4πx10^-7 m/A.
Physics
1 answer:
SSSSS [86.1K]2 years ago
5 0

Answer:

oh                      

Explanation:

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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> I NEED THE ANSWER NOW
FrozenT [24]
90 F = 43 OR 0.9F = 0.43
(F = 43 / 90 OR 0.43 / 0.9 =) 0.48 N

upwards force = downwards force
(R =) 1.2 N
5 0
3 years ago
What is the period of a wave with a frequency of 0.75 Hz?
Wewaii [24]

Answer:

Period = 1.33 seconds

Explanation:

Period = 1/0.75

8 0
2 years ago
What is your velocity if it takes you 40 seconds to walk around a circle of 50meters 3 times?​
Shtirlitz [24]

Answer:

0 m/s

Explanation:

Velocity is displacement over time.  Displacement is the distance between your initial position and your final position.  If you walk in a circle, you end up back where you started, so your displacement is 0.  Therefore, your velocity is also 0.

8 0
2 years ago
Read 2 more answers
friction between the tire of a moving car and the dry pavement is: A. static B. rolling C. sliding D. riding
qwelly [4]

Answer:A static

Explanation:

6 0
2 years ago
Can you answer this math homework? Please!
kap26 [50]

\large \mathfrak{Solution : }

9. An object which is in circular motion (moving along a circle) is said to be accelerating because it changes it's direction constantly even if it is moving with a constant speed. cuz acceleration is change in either magnitude or direction of an object with respect to time.

therefore, it's still acceleration as change in direction with time.

10. Average speed of an object can be calculated by dividing the total distance covered by an object by time taken to cover that distance.

i.e

  • \boxed{speed =  \dfrac{distance}{time} }

it can be re- arranged to find the distance as :

  • \boxed{distance = speed \times time}

  • time =  \dfrac{distance}{speed}

11. speed = 20 m/s : conversion into km/h

distance covered : 4 km = 4000 m

  • time =  \dfrac{distance}{speed}

  • t =  \dfrac{4000}{20}

  • t =  200 \:  \: sec

time taken = 200 seconds

12. let's use the first equation of motion to find the acceleration :

  • v = u + at

  • 50 = 80 + 120a

  • 50 - 80 = 120a

  • a =  \dfrac{ - 30}{120}

  • a = -   \dfrac{1}{4} m/s {}^{2}

  • - 0.25 \:  \: m/s {}^{2}
3 0
2 years ago
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