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3 years ago

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An inductor has an inductance of 0.12 mH. Calculate the number of turns per unit length of this inductor if it has a total of 50

0 turns in it. The cross-sectional area of the solenoid is 2.00 cm^2. Take μo = 4πx10^-7 m/A.

1 answer:

SSSSS [86.1K]3 years ago

5 0

Answer:

oh

Explanation:

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A rope of total mass m hnd length L is suspended vertically with an object of mass M suspended from the lower end. Find an expre

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Answer:

Part a)

$v = \sqrt{xg + \frac{MLg}{m}}$

Part b)

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Explanation:

Part a)

Tension in the rope at a distance x from the lower end is given as

$T = \frac{m}{L}xg + Mg$

so the speed of the wave at that position is given as

$v = \sqrt{\frac{T}{\mu}}$

here we know that

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now we have

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Part b)

time taken by the wave to reach the top is given as

$t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}$

$t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})$

$t = \frac{2}{9.8}(\sqrt{(39.2\times 9.8) + \frac{8(39.2)(9.8)}{1}})$

$t = 12 s$

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