Question

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = (x – 1). What is the slope-intercept form of the equation for this line?

Answer 1

You find the slope-intercept form by simplifying the point-slope equation. 
Slope-intercept formula: y = mx + b where m = slope and b = y-intercept
Observe. 

y - 3 = 1(x - 1) 
y - 3 = x - 1
   +3        + 3
y = x + 2 <----------------SI form = Answer
  

Answer 2

Answer:

$y = x +2$

Step-by-step explanation:

Given : The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3)

To Find: What is the slope-intercept form of the equation for this line?

Solution:

Slope intercept form : $y=mx+c$

Now we have to convert the given equation in this form.

$y - 3 = (x - 1)$

$y = (x - 1)+3$

$y = (x - 1)+3$

$y = x +2$

On comparing with general form m = 1

So, the slope-intercept form of the equation for this line is $y = x +2$