Answer:
Explanation:
Let the potential difference between the plate is V . Then in the first case
Electric field E between plate
E₁ = V / d
where d is separation between plate
When the plate separation becomes d / 2
Electric field E between plate
E₂ = V / d /2
= 2 V / d =2E₁
Or twice the earlier field
Answer:
58.8 Hz
Explanation:
The relationship between frequency and period of a wave is
where
f is the frequency
T is the period
For the wave in this problem, we know its period:
T = 0.017 s
Therefore, its frequency is
<span>C) An object accelerates in the same direction as that of the force applied.</span>
Answer:
the sheets approach while the object is near
Explanation:
An electroscope is an apparatus that has two metal sheets attached, when these sheets have a charge and distribute evenly between them and the sheets repel.
When I approach an object charged with a counter (negative) charge, part of the charge of the electroscope moves near the charged external object, to neutralize the electric field, so as the charge on one of the plates decreases the electroscope has approached , as the objects are not touched the system remains in this configuration while the object is close. When the object is released, the electric field it creates disappears, so the positive charges repel inside the electroscope and the sheets repel to the initial position.
In short, the sheets approach while the object is near
Answer:
A. Force on parent is greater than the force on child
B. The net force acting on the bodies is zero for each.
C. the drag force on the parent is greater than the drag force on the child.
Explanation:
The child and the parent jump together form a certain height where the mass of the parent is greater than the mass of the child.
A
Before opening the parachute the drag force is negligible and so their velocity and acceleration are same simultaneously. The total force acting on the child is lesser than the total force of gravity on the child because the force of gravity is given as:
where:
m= mass
g= acceleration due to gravity
So when the mass is greater then the force of gravity is also greater on the body.
B
During the uniform velocity motion there is no acceleration in the body and hence we can say the there is no net force acting on the body.
The net force acting on the body is zero.
C
The force of drag acts due to parachute on each of the body when falling with uniform motion, this drag force is equal to the force of gravity acting on each of them individually.
So the drag force on the heavier body is greater than the drag force on the lighter body. During this condition the bodies fall with a uniform velocity called terminal velocity.
where:
density of the air
A= area normal to the direction of fall
v= terminal velocity
coefficient of drag