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Virty [35]
3 years ago
7

Question 2 of 10

Physics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

2.00 A

Explanation:

Total resistance = 10 + 20 + 30 = 60 ohms

Potential difference (V) = 120volts

Current (I) =?

from Ohms law V = IR

==> I = V/R = 120/60 = 2 A

Note: for resistors in series equal amount of electric current flows through the circuit

You might be interested in
Who was the first known contributor to the atomic theory?
juin [17]

Answer:

Democritus

Explanation:

Democritus came up with the idea of indivisible atoms. The earliest known proponent of anything resembling modern atomic theory was the ancient Greek thinker Democritus. He proposed the existence of indivisible atoms as a response to the arguments of Parmenides and the paradoxes of Zeno.

6 0
3 years ago
Plz plz help ...i really need steps for this answer
bija089 [108]

Answer:

3.9 seconds

Explanation:

Use constant acceleration equation:

y = y₀ + v₀ t + ½ at²

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 15 m

v₀ = 15 m/s

a = -9.8 m/s²

Substituting values:

0 = 15 + 15t + ½ (-9.8) t²

0 = 15 + 15t − 4.9t²

0 = 4.9t² − 15t − 15

Solve with quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 15 ± √((-15)² − 4(4.9)(-15)) ] / 2(4.9)

t = [ 15 ± √(225 + 294) ] / 9.8

t = (15 ± √519) / 9.8

t = -0.79 or 3.9

It takes 3.9 seconds for the stone to reach the bottom of the well.

The negative answer is the time it takes the stone to travel from the bottom of the well up to the top of the well.

6 0
3 years ago
Read 2 more answers
scott and jafar are ready to work a problem. in this simulation, assume the coordinates of the points are as follows. a (0 s, 30
max2010maxim [7]

Answer:

Explanation:

point a represents time 0 and position coordinate 30

point b represents time 10 s , and position coordinate 50 m .

time elapsed = 10 - 0 = 10 s .

displacement = 50 m - 30 m

= 20 m

average velocity = displacement / time elapsed

= 20 / 10

= 2 m /s .

7 0
4 years ago
object carries a charge of -8.1 µC, while another carries a charge of -2.0 µC. How many electrons must be transferred from the
LenKa [72]

Number of electrons transferred: 1.91\cdot 10^{13}

Explanation:

The charge on the first object is

Q_1 = -8.1\mu C

while the charge on the 2nd object is

Q_2=-2.0 \mu C

When they are in contact, the final charge on each object will be

Q=\frac{Q_1+Q_2}{2}=\frac{-8.1+(-2.0)}{2}=-5.05 \mu C

So, the amount of charge (electrons) transferred from the 1st object to the 2nd object is

\Delta Q = Q_1 - Q = -8.1 -(5.05)=-3.05 \mu C = -3.05\cdot 10^{-6}C

The charge of one electron is

e=-1.6\cdot 10^{-19}C

Therefore, the number of electrons transferred is

N=\frac{Q}{e}=\frac{-3.05\cdot 10^{-6}}{-1.6\cdot 10^{-19}}=1.91\cdot 10^{13}

Learn more about electrons:

brainly.com/question/2757829

#LearnwithBrainly

8 0
3 years ago
Mr. Tolman believes that our universe is expanding, but with all of the gravitational force from the celestial bodies of space,
sattari [20]
The correct answer is A I believe but I may not be correct. Either A or B
8 0
3 years ago
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