C. Their strengths are added
what is the final speed of the incoming ball if it is much more massive than the stationary ball? express your answer using two significant figures. v1 = 200 m / s submitprevious answers correct
Perfectly elastic collisions means that both mechanical energy and
momentum are conserved.
Therefore, for this case, we have the equation to find the final velocity of the incoming ball is given by
v1f = ((m1-m2) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v1f: final speed of ball 1.
m1: mass of the ball 1
m2: mass of the ball 2
Since the mass of the ball 1 is much larger than the mass of the ball 2 m1 >> m2, then rewriting the equation:
v1f = ((m1) / (m1) v1i
v1f = v1i
v1f = 200 m / s
answer
200 m / s
part b part complete what is the final direction of the incoming ball with respect to the initial direction if it is much more massive than the stationary ball? forward submitprevious answers correct
Using the equation of part a, we can include in it the directions:
v1fx = ((m1-m2) / (m1 + m2)) v1ix
v1i: initial velocity of ball 1 in the direction of the x-axis
v1f: final speed of ball 1 in the direction of the x-axis
like m1 >> m2 then
v1fx = v1ix
v1fx = 200 m / s (positive x direction)
So it is concluded that the ball 1 continues forward.
answer:
forward
part c part complete what is the final speed of the stationary ball if the incoming ball is much more massive than the stationary ball ?.
The shock is perfectly elastic. For this case, we have that the equation to find the final velocity of the stationary ball is given by
v2f = ((2m1) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v2f: final speed of ball 2.
m1: mass of the ball 1
m2: mass of the ball 2
Then, as we know that m1 >> m2 then
v2f = ((2m1) / (m1) v1i
v2f = 2 * v1i
v2f = 2 * (200 m / s)
v2f = 400 m / s
answer
400m / s
Answer:
I think it will be half of the initial charge
Explanation:
Because we know, the resulting charge will be q1+q2/2, since one is neutral so the charge will be half q/2
Answer:
The electric field of an infinite line charge with a uniform linear charge density can be obtained by a using Gauss' law. Considering a Gaussian surface in the form of a cylinder at radius r, the electric field has the same magnitude at every point of the cylinder and is directed outward.
Answer:
Vf = 5.05 m/s
Explanation:
To know this, you need to use the expressions for free fall.
In this case, we only know the length of the stick which is 1.3 m.
The stick is held vertically and then is allowed to fall freely. Now, we want to know the final speed of the stick when it reach the floor.
In this case, we can assume that when the stick is allowed to fall, the innitial speed is 0. Then, the other thing we can assume is the height where the stick is put to fall. In this case, the height is the same as the length, because the stick is already on the floor but is standing vertically.
So, we have here the height, and if the stick is falling, is because of gravity, which is 9.8 m/s²
To calculate the speed, you can use this expression:
Vf = √2*g*h
Replacing the data we have:
Vf = √2 * 9.8 * 1.3
Vf = 5.05 m/s
