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tamaranim1 [39]
3 years ago
8

A cylindrical water tank has a height of 20cm and a radius of 14cm. If it is filled to 2/5 of its capacity, calculate.

Physics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

4.926 L Y 7.389 L

Explanation:

first you calculate the tank volume

V = π(14 cm)^{2}(10 cm = 12315 cm^{3}

then you convert to liters

12315 cm^{3} = 12.315 l

then you calculate the liters of water

2/5(12.35 l) = 4.926 l

finally we calculate the amount without water

12.315 l - 4.926 l = 7.389 l

HERE IS MORE INFORMATION ON THE SUBJECT. THEY REMOVED THE

ENGLISH SITE BUT YOU CAN USE TRANSLATOR

LINK: https://gscourses.thinkific.com/courses/fisicai

den301095 [7]3 years ago
5 0

Answer:

Explanation:

Total capacity is

V = πr²h = π(14²)(20) = 12,315 cm³

I. Quantity of water in the tank 12,315(2/5) = 4,926 cm³

II. Quantity of water left to fill the tank to its capacity.

12,315 - 4,926 = 7,389 cm³

or

12,315(3/5) = 7,389 cm³

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