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Andrei [34K]
3 years ago
7

A coin is flipped eight times, and the sequence of heads and tails occurring is recorded. How many distinct sequences are possib

le?
Mathematics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

256

Step-by-step explanation:

Here, the order of the results from each other doesn't matter. e.g HHHTTTTT, TTTTTHHH are two different outcomes.

There are two possible outcomes for each flip, heads,H or tails, T

After eight flips, using the rule of product, the possible outcomes or sequences is equal to

2x2x2x2x2x2x2x2= 2^8=256

General formula for total number of outcomes when a coin is flipped is given by 2 raised to power n, where n is the number of flips, in this case, n is 8,  2^8=256

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Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing
MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

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AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

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