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Andrei [34K]
3 years ago
7

A coin is flipped eight times, and the sequence of heads and tails occurring is recorded. How many distinct sequences are possib

le?
Mathematics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

256

Step-by-step explanation:

Here, the order of the results from each other doesn't matter. e.g HHHTTTTT, TTTTTHHH are two different outcomes.

There are two possible outcomes for each flip, heads,H or tails, T

After eight flips, using the rule of product, the possible outcomes or sequences is equal to

2x2x2x2x2x2x2x2= 2^8=256

General formula for total number of outcomes when a coin is flipped is given by 2 raised to power n, where n is the number of flips, in this case, n is 8,  2^8=256

You might be interested in
(x^2+3x+1)(x^2-2x+5)
deff fn [24]

Answer:

x^4 + x^3 + 13x + 5

Step-by-step explanation:

5 0
3 years ago
We are given a sequence of five non-zero numbers, where the sum of each term and its neighboring terms is 15 or 25. Find the sum
PSYCHO15rus [73]

We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.

We will see that the sum tends to infinity.

So we have 5 terms;

A, B, C, D, E.

We know that the sum of each term and its neighboring terms is 15 or 25.

then:

  • A + B + C = 15 or 25
  • B + C + D = 15 or 25
  • C + D + E = 15 or 25

Now, we want to find the sum of all the terms in the sequence (not only the 5 given).

Then let's assume we write the sum of infinite terms as:

a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + ...

Now we group that sum in pairs of 3 consecutive terms, so we get:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ...

So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.

Then we have:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) +  ... \to \infty

If you want to learn more, you can read:

brainly.com/question/21885715

3 0
2 years ago
tess has 100 dimes and quarters , if the total of the coins is $21.40 how many of each of the coins does she have ?? Using subst
Zanzabum

Answer: 24 and 76

Step-by-step explanation:

{

d

+

q

=

100

10

d

+

25

q

=

2140

From the first equation, we have  

d

=

100

−

q

Substituting that into the second equation, we have

10

(

100

−

q

)

+

25

q

=

2140

⇒

1000

−

10

q

+

25

q

=

2140

⇒

15

q

=

1140

⇒

q

=

1140

15

=

76

Knowing that  

q

=

76

we can substitute that value into the first equation to obtain

d

+

76

=

100

∴

d

=

24

Thus, Sue has  

24

dimes and  

76

quarters.

4 0
3 years ago
Please help with this question.
Lesechka [4]
The answer to your algerbra question is eight over y
4 0
3 years ago
Read 2 more answers
what is the probability of getting heads on flipping a coin and getting a number greater than or equal to 4 when rolling a singl
Andrew [12]
The answer is 25%.
hope this helps.
8 0
3 years ago
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