Answer: 22
Step-by-step explanation:
Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.
By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.
Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
Solve by back-calculating for the missing number . . . (58 - 7 - 14 + 3)/(5 × 2) = 4
Step-by-step explanation:
the proof is given above
125, 216, 343, 512, 729
the numbers given in the sequence are recognisable as cubes
1 = 1³, 8 = 2³, 27 = 3³, 64 = 4³
the next five terms will be
5³ = 125, 6³ = 216, 7³ = 343, 8³ = 512 and 9³ = 729