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Black_prince [1.1K]
3 years ago
13

The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1

0 ounces. Find the following: a.The net weight of the pigs in the truck. b. The weight of the empty truck
Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a  truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

1\text{ pound}=16\text{ ounces}

So,

\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}

Similarly,

\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}

So, Net weight of the pigs in the truck

1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .


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Answer:

step by step

STEP

1

:

Equation at the end of step 1

((((3•(m3))+5m2)-5m)+1)

(———————————————————————•m)-1

3

STEP

2

:

Equation at the end of step

2

:

(((3m3+5m2)-5m)+1)

(——————————————————•m)-1

3

STEP

3

:

3m3 + 5m2 - 5m + 1

Simplify ——————————————————

3

Checking for a perfect cube :

3.1 3m3 + 5m2 - 5m + 1 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 3m3 + 5m2 - 5m + 1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -5m + 1

Group 2: 5m2 + 3m3

Pull out from each group separately :

Group 1: (-5m + 1) • (1) = (5m - 1) • (-1)

Group 2: (3m + 5) • (m2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

3.3 Find roots (zeroes) of : F(m) = 3m3 + 5m2 - 5m + 1

Polynomial Roots Calculator is a set of methods aimed at finding values of m for which F(m)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers m which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 3 and the Trailing Constant is 1.

The factor(s) are:

of the Leading Coefficient : 1,3

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 8.00

-1 3 -0.33 3.11

1 1 1.00 4.00

1 3 0.33 0.00 3m - 1

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

3m3 + 5m2 - 5m + 1

can be divided with 3m - 1

Polynomial Long Division :

3.4 Polynomial Long Division

Dividing : 3m3 + 5m2 - 5m + 1

("Dividend")

By : 3m - 1 ("Divisor")

dividend 3m3 + 5m2 - 5m + 1

- divisor * m2 3m3 - m2

remainder 6m2 - 5m + 1

- divisor * 2m1 6m2 - 2m

remainder - 3m + 1

- divisor * -m0 - 3m + 1

remainder 0

Quotient : m2+2m-1 Remainder: 0

Trying to factor by splitting the middle term

3.5 Factoring m2+2m-1

The first term is, m2 its coefficient is 1 .

The middle term is, +2m its coefficient is 2 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 1 • -1 = -1

Step-2 : Find two factors of -1 whose sum equals the coefficient of the middle term, which is 2 .

-1 + 1 = 0

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

3

:

(m2 + 2m - 1) • (3m - 1)

(———————————————————————— • m) - 1

3

STEP

4

:

Equation at the end of step 4

m • (m2 + 2m - 1) • (3m - 1)

———————————————————————————— - 1

3

STEP

5

:

Rewriting the whole as an Equivalent Fraction

5.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

1 1 • 3

1 = — = —————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

5.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

m • (m2+2m-1) • (3m-1) - (3) 3m4 + 5m3 - 5m2 + m - 3

———————————————————————————— = ———————————————————————

3 3

Polynomial Roots Calculator :

5.3 Find roots (zeroes) of : F(m) = 3m4 + 5m3 - 5m2 + m - 3

See theory in step 3.3

In this case, the Leading Coefficient is 3 and the Trailing Constant is -3.

The factor(s) are:

of the Leading Coefficient : 1,3

of the Trailing Constant : 1 ,3

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -11.00

-1 3 -0.33 -4.04

-3 1 -3.00 57.00

1 1 1.00 1.00

1 3 0.33 -3.00

3 1 3.00 333.00

Polynomial Roots Calculator found no rational roots

Final result :

3m4 + 5m3 - 5m2 + m - 3

———————————————————————

3

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