Answer:
<em>B</em><em>.</em><em> </em><em>Kinetic</em><em> </em><em>friction</em><em> </em>
Explanation:
This is definitely the correct answer because kinetic friction acts when an object is in motion and it allows the object to move without slipping, etc
<em>ALSO</em><em>,</em><em> </em><em>PLEASE DO</em><em> </em><em>MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>
<em>Bonne</em><em> </em><em>journée</em><em> </em><em>;</em><em>)</em><em> </em>
Answer:
True
Explanation:
If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.
<u>Centrifugal force is mathematically related as:</u>
![F=m.r.\omega^2](https://tex.z-dn.net/?f=F%3Dm.r.%5Comega%5E2)
where:
m = mass of the revolving body
r = radius of revolution
angular velocity in radians per second
This force F acts in radially outward direction.
The type of relationship formed when a megabat eats a fig and drops the seeds in a new location is COMENSALISM. It is an ecological interaction.
<h3>What is commensalism?</h3>
Commensalism is a type of ecological interaction in which one organism benefits (in this case, the tree) and the other organism neither benefits nor harm (the megabat).
Mutualism is a type of ecological association in which both organisms benefit from such interaction.
Conversely, parasitism is a type of ecological interaction in which one organism benefits and the other organism is harmed.
Learn more about commensalism here:
brainly.com/question/16712254
Answer:
![\Rightarrow L=70 .03472 cm](https://tex.z-dn.net/?f=%5CRightarrow%20L%3D70%20.03472%20cm)
Explanation:
For convenience, let's represent the thermal expansion coefficient by
, i.e.
.
Given that, for steel
°
,
initial length,
, initial temperature,
°
, and the final temperature,
°
.
Let the length of the rod at
°
be
.
Now, change in length, ![\Delta L=\alpha L_0 \Delta T](https://tex.z-dn.net/?f=%5CDelta%20L%3D%5Calpha%20L_0%20%5CDelta%20T)
![\Rightarrow \Delta L=\alpha L_0 (T-T_0)](https://tex.z-dn.net/?f=%5CRightarrow%20%5CDelta%20L%3D%5Calpha%20L_0%20%28T-T_0%29)
![\Rightarrow L-L_0=1.24\times 10^{-5}\times 70 (110-70)](https://tex.z-dn.net/?f=%5CRightarrow%20%20L-L_0%3D1.24%5Ctimes%2010%5E%7B-5%7D%5Ctimes%2070%20%28110-70%29)
![\Rightarrow L-70=1.24\times 10^{-5}\times 70 \times 40](https://tex.z-dn.net/?f=%5CRightarrow%20L-70%3D1.24%5Ctimes%2010%5E%7B-5%7D%5Ctimes%2070%20%5Ctimes%2040)
![\Rightarrow L=70 + 0.03472 cm](https://tex.z-dn.net/?f=%5CRightarrow%20L%3D70%20%2B%200.03472%20cm)
![\Rightarrow L=70 .03472 cm](https://tex.z-dn.net/?f=%5CRightarrow%20L%3D70%20.03472%20cm)
Hence, the length of the rod at
°
be
.
Answer:
b) Distance covered before stopping.
Explanation:
If you want to find the distance d required to come to a stop starting at some initial speed v, with braking acceleration a, use the kinematic relation
vf2 - vi2 = 2ad
vi = initial speed at the moment braking begins = v
vf = final speed = 0 (comes to a full stop)
-v2 = 2ad
d = -v2/(2a)