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iogann1982 [59]
3 years ago
9

Which type of relationship is formed when a megabat eats a fig and drops the

Physics
1 answer:
Alina [70]3 years ago
3 0

The type of relationship formed when a megabat eats a fig and drops the seeds in a new location is COMENSALISM. It is an ecological interaction.

<h3>What is commensalism?</h3>

Commensalism is a type of ecological interaction in which one organism benefits (in this case, the tree)  and the other organism neither benefits nor harm (the megabat).

Mutualism is a type of ecological association in which both organisms benefit from such interaction.

Conversely, parasitism is a type of ecological interaction in which one organism benefits and the other organism is harmed.

Learn more about commensalism here:

brainly.com/question/16712254

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A sprinter starts from rest and accelerates to her maximum speed of 10.5 m/s in a distance of 11.0 m. (a) What was her accelerat
Anvisha [2.4K]

Answer:

a)a=5.01m/s^2

b)t=11.26s

Explanation:

A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf=Vo+a.t  (1)

{Vf^{2}-Vo^2}/{2.a} =X(2)

X=Xo+ VoT+0.5at^{2}    (3)

X=(Vf+Vo)T/2 (4)

Where

Vf = final speed

Vo = Initial speed

T = time

A = acceleration

X = displacement

In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve

to solve the question a, we can use the ecuation number 2

Vo=0

Vf=10.5 m/s

x=11m

{Vf^{2}-Vo^2}/{2.a} =X

{Vf^{2}-Vo^2}/{2.x} =a

{10.5^{2}-0^2}/{2x11} =a

a=5.01m/s^2

to find the time we can use the ecuation number 1

Vf=Vo+a.t

t=(Vf-Vo)/a

t=(10.5-0)/5.01=2.09s

part b

in this case  the spees is constant, so the movement is defined by the following ecuation

X=VT

t=x/v

t=96.3/10.5=9.17s

to find the total time we sum the times when the speed is constant and when the acceleration is constan

t=9.17+2.09

t=11.26s

8 0
3 years ago
The energy per unit volume in an electromagnetic wave is: ________
Marianna [84]

Answer:

c.

Explanation:

Electromagnetic waves are waves that are generated when an electric field and a magnetic field vibrate together. They are usually created whenever an electric field collides with a magnetic field.

In more generic terms for an electric field, the energy per unit volume is given by:

Energy density = \dfrac{1}{2}\varepsilon _oE^2

For magnetic field:

Energy density =\dfrac{\beta^2}{2 \mu _o}

∴

For the electromagnetic wave (u):

Total energy density is:

u = \dfrac{1}{2}\varepsilon_oE^2 + \dfrac{\beta ^2}{2 \mu_o}

Due to the fact that the energy related with both fields is equivalent:

Then:

E = cB

6 0
3 years ago
A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.65 m/s2 for 17.0 s. 2
nlexa [21]
Hello

Let's solve the problem in the three different steps

1) Uniformly accelerated motion, with acceleration a_1 = 2.65~m/s^2 and for a total time of t_1=17~s. The body is initially at rest, so the distance covered is given by
S= \frac{1}{2}a_1t_1^2=382.9~m
Calling v_f and v_i the final and initial velocity, and since the v_i=0~m/s because the body starts from rest, we can use
a= \frac{v_f-v_i}{t}
to find the final velocity after this first leg:
v_{f}=v_i+a_1t_1=45~m/s
And the average velocity in this first leg is
v_1= \frac{v_f+v_i}{2}=22.5~m/s

2) Uniform motion. The velocity is constant and it is equal to the final velocity of the first leg: v_2=45~m/s. This is also the average velocity of the second leg. 
The total time of this second leg is t_2=1.60~min = 96~s. The distance covered is given by
S_2=v_2t_2=45~m/s \cdot 96~s=4320~m

3) Uniformly decelerated motion, with constant deceleration of a_3=-9.39~m/s^2 and for a total time of t_3=4.8~s. Here, the initial velocity of the body is the final velocity of the previous leg, i.e. v_i=45~m/s. Therefore, the distance covered in this leg is given by
S_3=v_i t_3 + \frac{1}{2} a_3 t^2 =107.8~m
The final velocity in this leg is given by
v_f=v_i+at=45~m/s-9.39~m/s^2 \cdot 4.8~s = -0.07~m/s
The negative sign means that after decelerating, the body has started to go in the opposite direction. Similarly to step 1, the average velocity in this leg is given by
v_3 =  \frac{1}{2}(v_f+v_i)=  \frac{1}{2}(-0.07~m/s+45~m/s)=  22.5~m/s

4) Finally, the total distance covered in the motion is
S=S_1+S_2+S_3=382.9~m+4320~m+107.8~m=4810.7~m
To find the average velocity, we must "weigh" the average velocity of each leg for the correspondent time of that leg:
v_{ave}= \frac{v_1t_1+v_2t_2+v_3t_3}{t_1+t_2+t_3}=40.8~m/s
8 0
3 years ago
What produces the Coriolis Force on the movement of Earth's air masses?
Serjik [45]

Answer:

rotation of earth from West to East

5 0
3 years ago
A red apple reflects ______<br> light and absorbs all other<br> colours.
trasher [3.6K]

<em>A red apple reflects</em> <u>Red</u> <em>light and absorbs all</em> <em>other colours.</em>

4 0
3 years ago
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