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Alex Ar [27]
3 years ago
11

On a map of New Mexico, 1 cm represents 45 km. The distance from Albuquerque to Santa Fe is 2 cm. Find the actual distance. A. 9

0 km B. 22.5 km C. 15 km D. 60 km
Physics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

The Andrews is A. 90km

Explanation: so far 1cm is equal to 45km on the map. That Means that a unit distance on the map is actually 4, 500, 000units (i.e 45 x 1000 x 100) in real life.

So if 1 cm represents 45km

2cm will represent 2 x 45km which gives 90km.

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A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the
pantera1 [17]

Answer:

Explanation:

F = k*n

F = 30N

k = ???

N = 0.73 M

F = k* N

30N = k * 0.73

k = 30N / 0.73

k = 41.1

5 0
3 years ago
A cat (5kg) has a potential energy of 8J. The cat is stuck on top of a bookshelf and then falls off the bookshelf. What is the v
kolbaska11 [484]

Answer:

176J

Explanation:

the explanation is that before the cat hits the ground the amount of kinetic energy builds up making it so that there is more energy

8 0
2 years ago
Imagine that you have two marbles on a table. You roll one marbles towards another. When the marble collide, the marble at rest
Alika [10]

Because that's called friction. When to things collide it causes friction which makes them stop rolling>

8 0
3 years ago
HELP PLEASE PLEASE
marshall27 [118]
<h3>Answer:</h3>

Magnitude of Impulse: 30000 kg · m/s or 30000 N · s

Force on the Car: -6000 N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality<u> </u>

<u>Physics</u>

<u>Momentum</u>

  • Momentum Equation: P = mv
  • Impulse Equation: J = FΔt
  • Law of Conservation of Momentum
<h3>Explanation:</h3>

<u>Step 1: Define</u>

Mass <em>m</em> = 1.50 × 10³ kg

Velocity <em>v</em> = 20 m/s east

Change in time Δt = 5.00 s

<u>Step 2: Find Magnitude</u>

  1. Substitute [Momentum]:                    P = (1.50 × 10³ kg)(20 m/s)
  2. Multiply:                                              P = 30000 kg · m/s

<u>Step 3: Find Force</u>

<em>We use the Law of Conservation of Momentum to find our break force acting upon the car.</em>

  1. Substitute [Impulse]:                    30000 kg · m/s = F(5.00 s)
  2. Rewrite:                                        30000 N · s = F(5.00 s)
  3. Divide 5 on both sides:               6000 N = F
  4. Rewrite:                                        F = 6000 N

Since the car is deaccelerating, the break force would be towards the west direction (negative as east is our positive direction).

∴ F = -6000 N

4 0
3 years ago
Read 2 more answers
A box with a weight of 100 N rests on a horizontal floor. The coefficient of static friction is = 0,40 and the coefficient of ki
kompoz [17]
Weight=100N
SF=0.4
KF=0.3
Magnitude?
0.4 x 0.3 = 0.12
0.12x100=12
Ans =20
7 0
2 years ago
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