Answer:
A. a uniform mixture that can't be separated
ΔK = -2334.66J. The kinetic energy loss is -2334.66J.
This is an example of elastic collision which means that the two bodies remain united after the collision, as we know the amount of movement is preserved that is called conservation of momentum. So, we can write the equation as follow:
Where is the initial momentum and is the final momentum.
Substituting the values:
After the collision the bodies are united and move at the speed of 33.33 m/s.
To calculate the kinetic energy lost in the impact we only have to calculate the energy of each body before the impact and compare it with the energy of the whole after the impact.
ΔK =
ΔK =
Substituting the values:
ΔK =
ΔK =
ΔK =
ΔK =
ΔK =
ΔK =
Answer:
Explanation:
We shall apply conservation of mechanical energy law to solve the problem .
loss of height = L ( 1 - cos 37 ) where L is length of rope
loss of potential energy at the bottom = gain of kinetic energy .
mg L ( 1 - cos 37 ) = 1/2 m v² where v is velocity at the bottom
v² = 2 L g ( 1 - cos 37 )
= 2 x 10 x 9.8 ( 1 - cos 37 )
= 39.46
v = 6.28 m /s
8M.
Because it would acumúlate to it
Answer:
0.7549kg
Explanation:
The mass of the slice + mass of the remaining cake = total mass of cake.
mass of remaining cake = total mass of cake - the mass of the slice
total mass=0.870kg
mass of slice = 0.1151kg
mass of remaining cake = 0.870 - 0.1151
mass of remaining cake=0.7549kg