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ivolga24 [154]
3 years ago
7

How much energy is lost between trophic levels?

Physics
1 answer:
Wittaler [7]3 years ago
5 0
When energy transfers from one trophic level to next one, only 10% energy utilized by next trophic level & 90% is lost

In short, Your Answer would be 90%

Hope this helps!
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If my mass is 196 lbm and I tackle one of my teammates - while decelerating from a velocity of 6.7 m/s to 0 m/s in 0.5 s, how mu
Olin [163]

Answer:

the force acting on the team mate is 1.19 kN.

Explanation:

given,

mass = 196 lbm

while tackling, the deceleration is from velocity 6.7 m/s to 0 m/s

time taken for deceleration = 0.5 sec        

F = mass × acceleration

acceleration = \dfrac{0-6.7}{0.5}              

                     = -13.4 m/s²                            

1 lbs  = 0.453 kg                      

196 lbs = 196 × 0.453  = 88.79 kg

F = 88.79 × 13.4                              

F = 1189.786 N = 1.19 kN                      

hence, the force acting on the team mate is 1.19 kN.

8 0
3 years ago
Explain how water is controlled to generate electrical energy in hydro-electric dams. and show a diagram is help explain the ans
kirza4 [7]
Here is how I would I explain it. Water is channeled through tunnels in the dam. The energy of water flowing through the dam’s tunnels cause turbines to turn. The turbines make generators move. Generators are machines that produce electricity. Engineers control the amount of water let through the dam. The process used to control this flow of water is called the intake system.

Hope this helps can’t do the diagram part.
6 0
2 years ago
Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m
Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

so

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0
3 years ago
A book falls off a shelf that and hits the ground at 10.0 m/s. How far did it fall?
ELEN [110]

Answer:

Explanation:

14 m/s

Explanation:

The motion of the book is a free fall motion, so it is an uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. Therefore we can find the final velocity by using the equation:

where

u = 0 is the initial speed

g = 9.8 m/s^2 is the acceleration

d = 10.0 m is the distance covered by the book

Substituting data, we find

8 0
3 years ago
If the box moves at a constant velocity, what do you know about the forces acting on the object?
Anon25 [30]
The answer is A , the forces are balanced
6 0
3 years ago
Read 2 more answers
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