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Trava [24]
3 years ago
14

As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road i

s 100) A) static friction. B) kinetic friction. C) a combination of static and kinetic friction. D) neither static nor kinetic friction, but some other type of friction. E) It is impossible to tell what type of friction acts in this situation.
Physics
2 answers:
Verdich [7]3 years ago
7 0

Answer:

B) kinetic friction.

Explanation:

Remember that static friction is only the friction that is impeding the object from moving and in that matter, static friction is the amount of force necessary to make an object start to move from rest, the kinetic friction is the force needed to keep that object moving in that surface, since the car is not starting from rest we are only speaking about kinetic friction.

Kitty [74]3 years ago
6 0

Answer:

<em>B</em><em>.</em><em> </em><em>Kinetic</em><em> </em><em>friction</em><em> </em>

Explanation:

This is definitely the correct answer because kinetic friction acts when an object is in motion and it allows the object to move without slipping, etc

<em>ALSO</em><em>,</em><em> </em><em>PLEASE DO</em><em> </em><em>MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>

<em>Bonne</em><em> </em><em>journée</em><em> </em><em>;</em><em>)</em><em> </em>

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The plates of an isolated parallel plate capacitor are separated by a distance d and carry charge of magnitude q. The distance b
aleksklad [387]

The energy stored in the capacitor decreases to one-half (½) of its initial value when the distance between the plates is then reduced to d/2.

<h3>The energy stored in a capacitor.</h3>

Mathematically, the energy stored in a capacitor can be calculated by using this formula:

U = ½CV² or U = q²/2C

<u>Where:</u>

  • q is the charge.
  • C is the capacitance.
  • V is the potential difference.

Thus, we can logically deduce that the energy stored in the capacitor decreases to one-half (½) of its initial value when the distance between the parallel plate capacitors is reduced to d/2.

Read more on charge here: brainly.com/question/4313738

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4 0
2 years ago
The vertical displacement of the wave is measured from the what? And what is the term for vertical displacement?
navik [9.2K]

Explanation:

The vertical displacement of the wave is measured from the

equilibrium to the crest and is called the frequency.

crest to the trough and is called the amplitude.

trough to the trough and is called the wavelength.

equilibrium to the crest and is called the amplitude.

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5 0
3 years ago
Read 2 more answers
What is the standard unit of velocity
Bond [772]

Answer:

Explanation:

Meters per second

7 0
3 years ago
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An object has a mass of 785 g and a volume of 15 cm³. What is its density? (Give your answer in g/cm³ to 2 decimal places).
Anvisha [2.4K]

Answer:

denisity = 52.33 g/cm^{3}

Explanation:

Density:

d = \frac{m}{v}

We have that m = 785 and that v = 15 cm^{3}.

d = \frac{785}{15}

d = 52.33 m^{3}

4 0
3 years ago
Assume you have a rocket in Earth orbit and want to go to Mars. The required change in velocity is ΔV≈9.6km/s . There are two op
Nostrana [21]

Answer: Part 1: Propellant Fraction (MR) = 8.76

Part 2: Propellant Fraction (MR) = 1.63

Explanation: The Ideal Rocket Equation is given by:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

Where:

v_{ex} is relationship between exhaust velocity and specific impulse

\frac{m_{f}}{m_{e}} is the porpellant fraction, also written as MR.

The relationship v_{ex} is: v_{ex} = g_{0}.Isp

To determine the fraction:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

ln(MR) = \frac{v}{v_{ex}}

Knowing that change in velocity is Δv = 9.6km/s and g_{0} = 9.81m/s²

<u>Note:</u> Velocity and gravity have different measures, so to cancel them out, transform km in m by multiplying velocity by 10³.

<u />

<u>Part 1</u>: Isp = 450s

ln(MR) = \frac{v}{v_{ex}}

ln(MR) = \frac{9.6.10^{3}}{9.81.450}

ln (MR) = 2.17

MR = e^{2.17}

MR = 8.76

<u>Part 2:</u> Isp = 2000s

ln(MR) = \frac{v}{v_{ex}}

ln (MR) = \frac{9.6.10^{3}}{9.81.2.10^{3}}

ln (MR) = 0.49

MR = e^{0.49}

MR = 1.63

8 0
3 years ago
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