The area is 7, the width is 2 2/9 what is the length?

You decide to take advantage of the current online dating craze and start your own Web site. You know that you have 600 people w

Gnoma [55]

Answer:

1350

Step-by-step explanation:

Given:

Initial number of members = 600

Now,

Expected members = Initial members × ( 1 + r )ⁿ

by geometric progression

here,

r is the growth rate

n is the number of years

thus,

Number of members that expect at the end of 2 year

Expected members = Initial members × ( 1 + r )ⁿ

r = 25%

n = 2 years

Expected members = 600 × ( 1 + 0.25 )²

= 937.5

similarly,

Numbers of members that expect at the end of 3 year

Expected members = Initial members × ( 1 + r )ⁿ

r = 22%

n = 1 years (i.e after the end of 2 year)

Initial members = 937.5 (i.e after the end of 2 years is the initial for the starting of third year )

Expected members = 937.5 × ( 1 + 0.22 )¹

= 1143.75

Numbers of members that expect at the end of 4 year

Expected members = Initial members × ( 1 + r )ⁿ

r = 18%

n = 1 years (i.e after the end of 3 year)

Initial members = 1143.75 (i.e after the end of 3 years is the initial for the starting of fourth year )

Expected members = 1143.75 × ( 1 + 0.18 )¹

= 1349.625

Hence,

Total expected people = 1349.625 ≈ 1350

3 0

3 years ago

Elasticity of Demand The demand function for a certain brand of backpacks is

Trava [24]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:

P ( x ) = 50 Ln ( 50 / x ).

- The point price elasticity ( E ) of demand is given by:

$E = \frac{P}{x}*\frac{dP}{dx}$

- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.

- To determine the " dP / dx " by taking the first derivative of the given relation:

P ( x ) = 50 Ln ( 50 / x ).

d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]

= - 50 / x

- Hence the point price elasticity of demand is given by:

E = - ( P / x ) * ( 50 / x )

E = -50*P / x^2

- For an inelastic demand, ! E ! is < 1:

! -50*P / x^2 ! < 1

50*P / x^2 < 1

P < x^2 / 50

- For an unitary demand, ! E ! is = 1:

! -50*P / x^2 ! = 1

50*P / x^2 = 1

P = x^2 / 50

- For an inelastic demand, ! E ! is > 1:

! -50*P / x^2 ! > 1

50*P / x^2 > 1

P > x^2 / 50

2)

If the unit price is increased slightly from $50, will the revenue increase or decrease?

- We see from the calculated demand sensitivity d P / dt:

d P ( x ) / dx = - 50 / x

- We see that as P increases the from P = $50, the quantity of goods demanded would be:

50 = 50 ln(50/x)

1 = Ln ( 50 / x )

50/x = e

x = 50 / e

Then,

d P ( x ) / dx = - 50 / ( 50 / e )

d P ( x ) / dx = - e

- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.

- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:

Revenue R ( x ) = P ( x ) * x

= 50*x*ln(50/x)

Then the product of price and quantity goods also decreases; hence, revenue decreases.

8 0

3 years ago

Which of these numbers is classified as both real and rational 17 squared 23 squared 9 squared 2 squared

vovangra [49]

All of the given numbers are both real and rational, and so all of their respective squares are also real and rational.

3 0

2 years ago

Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0

Arada [10]

Answer:

$b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$

Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

After addition of two matrix we get

$\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

On equating both sides.

$b_{11}+15=1\Rightarrow b_{11}=-14$

$b_{12}-7=2\Rightarrow b_{12}=9$

$b_{13}+4=12\Rightarrow b_{13}=8$

$b_{21}+0=4\Rightarrow b_{21}=4$

$b_{22}+1=0\Rightarrow b_{22}=-1$

$b_{23}+2=2\Rightarrow b_{23}=0$

Therefore, the elements of matrix B are $b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$ .

3 0

2 years ago

What is the solution to this inequality x/10+6>8

topjm [15]

The answer to this would be x = 20

6 0

2 years ago

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