Question

A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this string is 402 m/s, how many antinodes are there in the standing wave?

Answer 1

Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{402}{603}$

$\lambda = 0.67\ m$

Number of anti nodes in the standing wave

$n=\dfrac{l}{\frac{\lambda}{2}}$

$n=\dfrac{2l}{\lambda}$

$n=\dfrac{2\times 1.33}{0.67}$

n =3.97= 4.

Number of antinodes is equal to 4.