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maria [59]
3 years ago
9

PLEASE HELP 25 POINTS (WILL AWARD BRAINIEST ANSWER)

Physics
1 answer:
Alona [7]3 years ago
7 0
D. The measure of average kinetic energy of molecules of a substance
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The earth's radius is 6.37×106m; it rotates once every 24 hours.What is the speed of a point on the earth's surface located at 3
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v = 120 m/s

Explanation:

We are given;

earth's radius; r = 6.37 × 10^(6) m

Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s

Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.

The angle will be;

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θ = 67.5

¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.

The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:

v = r(cos θ) × ω

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Approximation to 2 sig. figures gives;

v = 120 m/s

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