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shutvik [7]
3 years ago
12

Helppppppppppppp it’s timedddddddddd

Chemistry
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

Ok what do you need help with?

Explanation:

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Nuclear fusion differs from nuclear fission because nuclear fusion reactions- True or False
White raven [17]

I think the answer would be True

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3 years ago
The public is not yet able to ourchase cars powered by hydrogen fuel cells because engineers have to determine how the cars perf
disa [49]

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in real-world conditions

Explanation:

8 0
3 years ago
Phosphoric acid has 3 pka values, which are 2.1, 6.9, and 12.4. draw the protonated form of phosphoric acid associated with the
Margaret [11]
As mentioned above, phosphoric acid has 3 pKa values, and after 3 ionization it gives 3 types of ions at different pKa values:

H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq)         pKₐ₁ 
<span>

</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq)       pKₐ₂


HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq)          pKₐ₃ 


At the highest pKa value (12.4) of phosphoric acid, the last OH group will lose its hydrogen. On the picture I attached, it is shown required protonated form of phosphoric acid before reaction whose pKa value is 12.4.


6 0
4 years ago
Children tend to resemble their parents in many ways; they may have like eye color, hair texture, height, or skin tone. This is
weeeeeb [17]

black would be BB .

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5 0
3 years ago
Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
DanielleElmas [232]

Answer:

74.4 ml

Explanation:

          C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given     15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0
3 years ago
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