<u>Given:</u>
Mass of solvent water = 4.50 kg
Freezing point of the solution = -11 C
Freezing point depression constant = 1.86 C/m
<u>To determine:</u>
Moles of methanol to be added
<u>Explanation:</u>
The freezing point depression ΔTf is related to the molality m through the constant kf, as follows:
ΔTf = kf*m
where ΔTf = Freezing point of pure solvent (water) - Freezing pt of solution
ΔTf = 0 C - (-11.0 C) = 11.0 C
m = molality = moles of methanol/kg of water = moles of methanol/4.50 kg
11.0 = 1.86 * moles of methanol/4.50
moles of methanol = 26.613 moles
Ans: Thus around 26.6 moles of methanol should be added to 4.50 kg of water.
Answer:
Substances 1 and 2
Explanation:
an element only has 1 kind of atoms :3
Answer:
4.09×10⁻³ is the mole fraction of sucrose
Explanation:
Mole fraction = Moles of solute or solvent/ Total moles
Let's convert the mass to moles (mass / molar mass)
38.6 g / 342 g/m = 0.113 moles of sucrose
495 g / 18 g/m = 27.5 moles of water
Total moles = 0.113 m + 27.5 m = 27.0613 moles
Mole fraction of sucrose = Moles of sucrose / Total moles
0.113 m / 27.0613 moles = 4.09×10⁻³
Answer:
the process of carrying light
The segment that represents melting is time (minutes) and temperature.
