Answer:
2 NaOH + H2SO4 2 H2O + Na2SO4
How many grams of sodium sulfate will be formed if you start with 200.0
grams of sodium hydroxide and you have an excess of sulfuric acid?
355.3 grams of Na2SO4
200.0 g NaOH 1 mol NaOH 1 mol Na2SO4 142.1 g Na2SO4
40.00 g NaOH 2 mol NaOH 1 mol Na2SO4
= 355.3 g
Explanation:
The total number of lone pairs of electrons in N2O3 is 8.
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