Check out the attached image.
Figure 1 moves to figure 2 after the translation rule (x,y) ---> (x+1, y+2)
Figure 2 moves to figure 3 after the rotation 90 degrees clockwise around the origin
Figure 3 moves to figure 4 after the translation rule (x,y) ---> (x+2, y-3)
Figure 4 is in quadrant IV. The size does not change
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Answer: Choice B) Quadrant IV; no
5x – 1 = 3x – 15
Subtraction Property of Equality (Subtract 3x from both sides)
2x - 1 = -15
Addition Property of Equality (Add 1 to both sides)
2x = - 14
Division Property of Equality (Divide both sides by 2)
x = -7
Answer:
5 is the answer. hhhjjh y fl jj g gshwhwjqjajajw
Answer:
0.03865
Step-by-step explanation:
Since the true density for the two types of trees are given, we would evaluate the average for both of them
Low percentage of juvenile wood density = 0.523 and 0.0543
Average density = 0.523 + 0.0543/2
Average density = 0.55015
Moderate percentage of juvenile wood density = 0.489 and 0.0450
Average density = 0.489 + 0.0450/2
Average density = 0.5115
Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150
= 0.03865
<span>monoalphabetic cipher uses a fixed subtitution over the entire message</span>