The answers are
a) the domain is all real numbers
d) the input to an exponential function is the exponent
e) the base represents the multiplicative rate of change
hope this helps :)
Here is the formula for finding a partitioning point:
x=x1+k(x2-x1), y=y1+k(y2-y1)
k is the ratio of the segment from the beginning point to the partitioning : the whole segment. In this case, k=AP:AB=5/16
so x=1+(5/16)*(-2-1)=1/16
y=6+(5/16)(-3-6)=51/16
so the answer is (-1/16, 51/16)
Please double check my calculation by yourself.
refer to this website for the formula and how to find k:
"This ratio is called k, and is determined by writing the numerator over the sum of the numerator and the denominator of the original ratio."
https://cobbk12.blackboard.com/bbcswebdav/institution/eHigh%20School/Courses/CCVA%20CCGPS%20Coordina....
This is true. The numbers being arranged differently in this does not mean it'll not equal each other.
The exponential function with a growth factor has a rate greater than 1
The percentage growth rate is 276%
<h3>How to determine the percentage growth rate?</h3>
The growth factor (b) is given as:
b = 3.76
The growth factor (b) is greater than 1.
So, the percentage growth rate (r) is calculated as:
r = b - 1
Substitute known values
r = 3.76 - 1
Evaluate the difference
r = 2.76
Express as percentage
r = 276%
Hence, the percentage growth rate is 276%
Read more about exponential functions at:
brainly.com/question/11464095
Answer:
The correct option is 3.
Step-by-step explanation:
It is given that the length of a rectangle is represented by the function
![L(x)=4x](https://tex.z-dn.net/?f=L%28x%29%3D4x)
The width of that same rectangle is represented by the function
![W(x)=7x^2-4x+2](https://tex.z-dn.net/?f=W%28x%29%3D7x%5E2-4x%2B2)
The area of a rectangle is
![A=length \times width](https://tex.z-dn.net/?f=A%3Dlength%20%5Ctimes%20width)
![A=L(x) \times W(x)](https://tex.z-dn.net/?f=A%3DL%28x%29%20%5Ctimes%20W%28x%29)
![(L\cdot W)(x)=L(x) \times W(x)](https://tex.z-dn.net/?f=%28L%5Ccdot%20W%29%28x%29%3DL%28x%29%20%5Ctimes%20W%28x%29)
![(L\cdot W)(x)=4x\times(7x^2-4x+2)](https://tex.z-dn.net/?f=%28L%5Ccdot%20W%29%28x%29%3D4x%5Ctimes%287x%5E2-4x%2B2%29)
![(L\cdot W)(x)=28x^3-16x^2+8x)](https://tex.z-dn.net/?f=%28L%5Ccdot%20W%29%28x%29%3D28x%5E3-16x%5E2%2B8x%29)
Therefore option 3 is correct.