Answer:
<em>A ≈ 28.5</em>
Step-by-step explanation:
a, b, c
P = a + b + c
Semiperimeter s =
A =
~~~~~~~~~~~~~~~
= 4.3 + 2.89 + 6.81 = 14
s = 14 ÷ 2 = 7
=
= √14.75901 ≈ 3.84
= 8.59 + 7.58 + 6.81 = 22.98
s = 22.98 ÷ 2 = 11.49
=
= √609.7343148 ≈ 24.6928
= 3.84 + 24.6928 ≈ <em>28.5</em>
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,
Since, given the difference of the squares of the numbers is 5 that is
And the product of the numbers is 6 that is
Using identity, we have,
Substitute, we have,
Simplify, we have,
Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
9514 1404 393
Answer:
C. Obtuse
Step-by-step explanation:
The "form factor" I use for this is ...
a^2 + b^2 - c^2 = 6^2 + 8^2 - 11^2 = 36 +64 -121 = -21
The value is negative, indicating an OBTUSE triangle.
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<em>Additional comment</em>
In this expression, 'a' and 'b' are the two shortest sides (in no particular order) and 'c' is the longest side. The interpretation is ...
negative — obtuse
zero — right
positive — acute
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If you're familiar with Pythagorean triples, you know that the 3-4-5 right triangle triple can be doubled to give 6-8-10. The long side of 11 is longer than the hypotenuse for the right triangle, so would correspond to a largest angle greater than 90°. The 6-8-11 triangle would be OBTUSE.
