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adoni [48]
4 years ago
10

I need help solving this

Mathematics
2 answers:
Temka [501]4 years ago
4 0

subtracting 9.1 - 12.9 is -3.8

Vlad1618 [11]4 years ago
4 0
Just do
12.9 - 9.1 which is 3.8
then put a negative sign because yor negative # has a higher absolute value ( simply bigger)
the answer would be -3.8
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What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

5 0
3 years ago
Work out (8x10^-3) x (2x10^-4)​
love history [14]

Answer:

1.6 \times 10^{-6}

Step-by-step explanation:

(8 \times 10^{-3}) \times (2 \times 10^{-4})

8 \times 2 \times 10^{-3} \times 10^{-4}

16 \times 10^{-3+(-4)}

16 \times 10^{-3-4}

16 \times 10^{-7}

1.6 \times 10^{-6}

3 0
4 years ago
Read 2 more answers
Solve tan^2 (x) + 3 = 0 for 0 ≦ x < 360∘
creativ13 [48]

Answer:

d) none of the above

Step-by-step explanation:

correct me if wrong .

6 0
3 years ago
How many real solutions if any, does 2x^2-3x+8=0​
fenix001 [56]

Answer:

The quadratic equation 2\, x^{2} - 3\, x + 8 = 0 has no real solution.

Step-by-step explanation:

Rewrite the quadratic equation 2\, x^{2} - 3\, x + 8 = 0 in the standard form a\, x^{2} + b\, x + c = 0:

2\, x^{2} + (-3)\, x + 8 = 0, for which:

  • a = 2.
  • b = (-3).
  • c = 8.

The quadratic discriminant of a\, x^{2} + b\, x + c = 0 is (b^{2} - 4\, a\, c).  The quadratic discriminant of 2\, x^{2} + (-3)\, x + 8 = 0 would be:

\begin{aligned}& b^{2} - 4\, a\, c \\ =\; & (-3)^{2} - 4 \times 2 \times 8 \\ =\; & (-55)\end{aligned}.

Since the quadratic discriminant of this equation is negative, this quadratic equation has no real solution.

3 0
2 years ago
Kai needs to replace the strip laminate that is glued to the vertical faces on a square tabletop. The tabletop is 1.69 m2. What
son4ous [18]

Area of a square = Side x Side (length x width)

A = 1.69 m²

Length = √area of square

L = √1.69 m²

L = 1.3 m

Check Work: 1.3² = 1.3 m x 1.3m

= 1.69 m²

5 0
3 years ago
Read 2 more answers
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