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Inessa05 [86]
3 years ago
6

Which one of these statements is not true?

Physics
1 answer:
natka813 [3]3 years ago
3 0

Answer:d

Explanation:

It’s right

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Which of the following statements is correct about the force of gravity between two objects
Aneli [31]

Answer:

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Explanation:

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4 0
3 years ago
A 1000 Kg car approaches an intersection traveling north at 30 m/s . A 1250 Kg car approaches the same intersection traveling ea
Feliz [49]

Answer:

The final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.

Explanation:

Taking north direction as positive y axis and east direction as positive x axis .

Given:

Mass of first car is, m_1=1000\ kg

Initial velocity of first car is, u_1=30\vec{j}\ m/s

Mass of second car is, m_2=1250\ kg

Initial velocity of second car is,

Let the combined final velocity after collision be 'v' m/s with as components of final velocity along east and north directions respectively.

Now, as the net external force is zero, momentum is conserved for the two car system along the east and north directions.

Conserving momentum along the east direction, we have:

Initial momentum = Final momentum

m_1u_{1x}+m_2u_{2x}=(m_1+m_2)v_x\\\\0+1250\times 39=(1000+1250)v_x\\\\v_x=\frac{48750}{2250}\\\\v_x=\frac{65}{3} m/s

There is no component of initial velocity for first car in east direction, as it is moving in the north direction. So,

Now, conserving momentum along the north direction, we have:

Initial momentum = Final momentum

m_1u_{1y}+m_2u_{2y}=(m_1+m_2)v_y\\\\1000\times 30+0=(1000+1250)v_y\\\\v_y=\frac{30000}{2250}\\\\v_y=\frac{40}{3}\ m/s

There is no component of initial velocity for second car in north direction, as it is moving in the east direction. So, u_{2y}=0.

The magnitude of final velocity is given as:

|\vec{v}|=\sqrt{(v_x)^2+(v_y)^2}\\\\|\vec{v}|=\sqrt{(\frac{65}{3})^2+(\frac{40}{3})^2}\\\\|\vec{v}|=\sqrt{\frac{5825}{9}}=25.44\ m/s

The direction is given as:

\theta=\tan^{-1}(\frac{v_y}{v_x})\\\\\theta=\tan^{-1}(\frac{\frac{40}{3}}{\frac{65}{3}})=31.61^\circ

So, the final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.

7 0
3 years ago
(help asap will rate and thank) Compare the potential energy of a 5 lb ball at the top of a 5 foot hill and a 5 lb ball at the t
erastova [34]
1. is c and 2. is A because its POTENTIAL 
6 0
3 years ago
Read 2 more answers
If<br> f(x) = 5x - 20<br> find f(y +2)
olga2289 [7]

Answer:

f(y)=2

Explanation:

5x/5-20/5

x=4

f(y+2)=4

    -2   -2

f(y)=2

8 0
3 years ago
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