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Solnce55 [7]
2 years ago
13

How long does it take light from a camera to travel to the face of someone standing 7 meters away?

Physics
1 answer:
mestny [16]2 years ago
8 0

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

<h3>Speed = distance / time </h3>

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

<h3>Time =?</h3>

Time = Distance / speed

Time = 7 / 3×10⁸

<h3>Time = 2.33×10¯⁸ s</h3>

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Learn more: brainly.com/question/14988345

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The burning of a log releases the logs chemical_energy into other forms of energy
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Answer:

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Explanation:

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3 years ago
Mechanical energy is conserved in the presence of which of the following types of forces?magnetic
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<h2>Answer: electrostatic and gravitational force </h2><h2 />

Mechanical energy remains constant (conserved) if only <u>conservative forces</u> act on the particles.  

In this sense, the following forces are conservative:  

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-Elastic

-Electrostatics  

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3 years ago
Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v
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Answer:

A)Object 1 has the greater magnitude of its momentum.

B)The objects 2 have the greater kinetic energy.

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For object 1 :

v₁ = v  ,m₁ = 2 m

For object 2 :

v_2=2\sqrt{v} ,m₂=m

We know that linear momentum given as

P = M V

M=Mass , V=Velocity

For object 1 :

P₁ =m₁ v₁

P₁ =2 m v

For object 2

P_2=m_2v_2

P_2=2m\sqrt {v}

We can say that object 1 have more momentum.

The kinetic energy

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KE_2=\dfrac{1}{2}\times m\times 4v^2

KE_2=2mv^2

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