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3 years ago

How does upwelling affect the weather of a coastal region?

Physics

2 answers:

Bezzdna [24]3 years ago

8 0

Answer:A

Explanation:

Because if you look a the sentences it tells u but you have to look into more

SIZIF [17.4K]3 years ago

4 0

c.The warm surface water results in moist air and more rainfall.

Explanation:

During upwelling, cold water in the ocean is stirred up and brought to the surface.
The warmer surface water is then taken into deeper parts of the ocean.
Upwelling allows for nutrient mixing in the ocean and allows for useful gases to circulate well.
The warm surface water causes the air to be moisty.
When the air is carried landward towards the coast, it leads to rainfall when the saturated air releases the water.
The air then becomes cold and dry and it rises up.
Therefore, warm surface water results in moist air and more rainfall.

Learn more:

Ocean current brainly.com/question/4117397

#learnwithBrainly

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To test the performance of its tires, a car

velikii [3]

Answer:

The coefficient of static friction between the tires and the road is 1.987

Explanation:

Given:

Radius of the track, r = 516 m

Tangential Acceleration $a_r$ = 3.89 m/s^2

Speed,v = 32.8 m/s

To Find:

The coefficient of static friction between the tires and the road = ?

Solution:

The radial Acceleration is given by,

$a_{R = \frac{v^2}{r}$

$a_{R = \frac{(32.8)^2}{516}$

$a_{R = \frac{(1075.84)}{516}$

$a_{R = 2.085 m/s^2$

Now the total acceleration is

$\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2$

=> $= \sqrt{ (a_r)^2+(a_R)^2}$

=> $\sqrt{ (3.89 )^2+( 2.085)^2}$

=> $\sqrt{ (15.1321)+(4.347)^2}$

=> $19.4791 m/s^2$

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of static friction is

$\mu =\frac{f}{W}$

From (1) and (2)

$\mu =\frac{ma}{mg}$

$\mu =\frac{a}{g}$

Substituting the values, we get

$\mu =\frac{19.4791}{9.8}$

$\mu =1.987$

8 0

3 years ago

What is the humidity if the dry-bulb is 10℃ and the wet-bulb is 6℃?

LenaWriter [7]

Answer:

$Hello,~There!$

What is the humidity if the dry-bulb is 10℃ and the wet-bulb is 6℃?

<h2>33% According to the Graph</h2>

Hope this helps!

6 0

3 years ago

Two light bulbs are 2.0 m apart. From what distance can these light bulbs be marginally resolved by a small telescope with a 4.5

andrezito [222]

Answer:

R = 1.2295 10⁵ m

Explanation:

After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body

θ = 1.22 λ / D

where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture

how angles are measured in radians

θ = y / R

where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens

$\frac{y}{R} = 1.22 \frac{ \lambda}{D}$

R = $\frac{ y \ D}{1.22 \lambda}$

let's calculate

R = $\frac{ 2 \ 0.045}{ 1.22 \ 600 \ 10^{-9}}$

R = 1.2295 10⁵ m

3 0

3 years ago

a 10kg cement block horizontally at 6 m/s plows into a bank of sand and comes to a stop in 2.0 m/s. What is the average impact f

Gnesinka [82]

I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.

$\bar Ft = \Delta mv \\ \\ \bar F = \frac{\Delta mv }{t} \\ \\ \bar F \ avarage \ Force \\ m \ momentum \\ v \ velocity \\ t \ time$

7 0

4 years ago

Is mercury a terrestrial or gaseous planet

liraira [26]

Mercury a terrestrial. It isn't made of gas.

8 0

3 years ago