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Pie
3 years ago
12

How does upwelling affect the weather of a coastal region?

Physics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer:A

Explanation:

Because if you look a the sentences it tells u but you have to look into more

SIZIF [17.4K]3 years ago
4 0

c.The warm surface water results in moist air and more rainfall.

Explanation:

  • During upwelling, cold water in the ocean is stirred up and brought to the surface.
  • The warmer surface water is then taken into deeper parts of the ocean.
  • Upwelling allows for nutrient mixing in the ocean and allows for useful gases to circulate well.
  • The warm surface water causes the air to be moisty.
  • When the air is carried landward towards the coast, it leads to rainfall when the saturated air releases the water.
  • The air then becomes cold and dry and it rises up.
  • Therefore, warm surface water results in moist air and more rainfall.

Learn more:

Ocean current brainly.com/question/4117397

#learnwithBrainly

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A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3.0 km/h
Yuki888 [10]

Answer:

The magnitude of F₁ is 3.7 times of F₂

Explanation:

Given that,

Time = 10 sec

Speed = 3.0 km/h

Speed of second tugboat = 11 km/h

We need to calculate the speed

v_{1}=\dfrac{3.0\times10^{3}}{3600}

v_{1}=0.833\ m/s

The force F₁is constant acceleration is also a constant.

F_{1}=ma_{1}

We need to calculate the acceleration

Using formula of acceleration

a_{1}=\dfrac{v}{t}

a_{1}=\dfrac{0.833}{10}

a_{1}=0.083\ m/s^2

Similarly,

F_{2}=ma_{2}

For total force,

F_{3}=F_{2}+F_{1}

ma_{3}=ma_{2}+ma_{1}

The speed of second tugboat is

v=\dfrac{11\times10^{3}}{3600}

v=3.05\ m/s

We need to calculate total acceleration

a_{3}=\dfrac{v}{t}

a_{3}=\dfrac{3.05}{10}

a_{3}=0.305\ m/s^2

We need to calculate the acceleration a₂

0.305=a_{2}+0.083

a_{2}=0.305-0.083

a_{2}=0.222\ m/s^2

We need to calculate the factor of F₁ and F₂

Dividing force F₁ by F₂

\dfrac{F_{1}}{F_{2}}=\dfrac{m\times0.83}{m\times0.22}

\dfrac{F_{1}}{F_{2}}=3.7

F_{1}=3.7F_{2}

Hence, The magnitude of F₁ is 3.7 times of F₂

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