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katen-ka-za [31]

3 years ago

10

Find the 31st term of the sequence {7, 11, 15, 19, 23,....}

1 answer:

weeeeeb [17]3 years ago

3 0

It is adding 4 every time.

7 is the first term.
To get the 31st term, add 30*4 to 7 (why?)
The 31st term is 7+30*4=127

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Anyone knows #3 and 4 answers ?

UNO [17]

3.saven. 4.2and5 Third

4 0

3 years ago

Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative

SVETLANKA909090 [29]

I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.

Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.

7 0

3 years ago

Read 2 more answers

Solve for the roots in simplest form by completing the square <br><br> x^2-12x+20=0

Alex17521 [72]

Answer:

x = 10 or x = 2

Step-by-step explanation:

Solve for x:

x^2 - 12 x + 20 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 20 from both sides:

x^2 - 12 x = -20

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 36 to both sides:

x^2 - 12 x + 36 = 16

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 6)^2 = 16

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 6 = 4 or x - 6 = -4

Hint: | Look at the first equation: Solve for x.

Add 6 to both sides:

x = 10 or x - 6 = -4

Hint: | Look at the second equation: Solve for x.

Add 6 to both sides:

Answer: x = 10 or x = 2

5 0

3 years ago

Given that the image below is not drawn to

Natali [406]

Answer:

what image i dont see an image

Step-by-step explanation:

4 0

3 years ago

Find the distance between the two points (-10,3) and (0,27)

crimeas [40]

Answer:

26 units

Step-by-step explanation:

$\boxed{distance \: between \: 2 \: points = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } }$

Using the formula above,

distance between (-10, 3) and (0, 27)

$= \sqrt{ {( - 10 - 0)}^{2} + {(3 - 27)}^{2} }$

$= \sqrt{ {10}^{2} + ( - 24) {}^{2} }$

$= \sqrt{100 + 576}$

$= \sqrt{676}$

= 26 units

5 0

3 years ago