It will be hotter and more like than 20celium degrees
Answer:
Effective half-time of the tracer is 3.6 days
Explanation:
The formula for calculating the decay due to excretion for the first process is ;

here ;
= initial number of tracers
Then to the second process ; we have :

The total decay is as a result of the overall process occurring ; we have :
------ (1)
here ;

Putting the values in (1);we have :


As we also know that:
![\frac{1}{t_{1/2}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bt_%7B1%2F2%7D%7D%20%3D%20%5Cfrac%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2B%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2A%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D)
![\frac{1}{t_{1/2}}_{effective}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bt_%7B1%2F2%7D%7D_%7Beffective%7D%7D%20%3D%20%5Cfrac%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2B%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2A%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D)



= 3.6 days
The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.
Answer:
a) Angular speed(w) = 2.02rad/sec
b) 73J ( It is Inelastic Collision)
Explanation:
Given:
Mass=45kg
Length on each side = 1.5m side which is hangs vertically from a frictionless pivot at the center of its upper edge.
We need to calculate
(a) What is the angular speed and
(b) To know why the angular momentum conserved but not the linear momentum
CHECK THE ATTACHMENT FOR DETAILED EXPLATION
That the moon has soil within its shadowy craters rich and useful material