Answer:
the frequency of the hummingbird is 80 Hz.
Explanation:
Given;
number of times the hummingbird beats its wings, n = 4,800 times
the duration of this motion, t = 1 minute
The frequency of the hummingbird wings is calculated as follows;
Therefore, the frequency of the hummingbird is 80 Hz.
Answer: 34.9 cm
Explanation:
You are given the following parameters;
Object distance U = 32 cm
Magnification M = - 12.0
According to formula for magnification;
M = V/U
Where V = image distance.
Substitute V and M into the formula
-12 = V/32
Cross multiply
V = -12 × 32
V = - 384
You can use the formula
1/f = 1/V + 1/U
Where f = focal length
Substitute V and U into the formula
1/f = - 1/384 + 1/32
Find the lowest common factor of the denominator at Left hand side
1/f = ( -1 + 12 ) / 384
1/f = 11/384
Reciprocate both sides
F = 384/11
F = 34.9 cm
He should therefore use the focal length of 34.9 cm
R =
r - displacement or height
t - time taken
g = 10 m/s-2
t = square root from 2r/g =
= 1.5 seconds
Answer:
(Example Person) has to push hard to get the skateboard started, but once it begins moving, it takes much less effort to keep it rolling over the smooth, flat pavement. In fact, if (Example Person) tries to stop the rolling skateboard, it may take as much effort to stop it as it did to start it rolling in the first place.
Explanation:
Hope this helps :)
Answer:
1 st question: Control variable
2nd question: random variable
3rd question: if the two objects are dropped from the same height they will hit the ground at the same time
