A measure of the amount of light received on Earth is a star's ____.
2 answers:
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Answer:
The final speed will be the same for the children on the shorter side and on the longer side.
Explanation:
This is because since the they are the same distance above the ground, their potential energy which is a function of mass, acceleration due to gravity and vertical height are the same.
PE = Mass × gravity × vertical height
At this point, we can deduce that the horizontal length of the slide has no effect on the potential energy. Only the vertical height does.
All this potential energy is converted to kinetic energy at the end of the slide. Since the potential energy is the same, then the kinetic energy will be the same and thus their velocity is the same.
Mathematically, consider that PE = mgh and KE = m
at the bottom of the slide, since energy has to be conserved, PE must be equal to KE.
mgh = m
final velocity of the child , v =
It shows the final velocity is only a function f acceleration due to gravity and height.
Thus, making their velocities equal.
Answer:
A.) The arrow`s range is 624,996 m
B.) The arrow`s range is 846.887 m, when the horse is galloping
Explanation:
We have a case of oblique movement. In these cases the movement in the X axis is a Uniform Rectelinear Movement (URM), and a Uniform Accelerated Movement (UAM) in the Y axis.
By the way, the equations that we use for the X axis will be from URM, and those for the Y axis wiil be from UAM.
<u>Equations</u>
X axis:
Y axis:
A.) First, it is necessary to know t, total time.
To figure out t value, we use UAM, since time is determined by this movement.
Now, at the end of the movement, , then
Caculate the segcond degree equation to obtain the two possible values for t:
But, in physics, time it could not be negative, so we take
Caculate now:
B.) Now, the narrow has an additional speed, that could be sum to the speed due to the bow.
Using the same procedure that item A, caculate X
First, we need to know the new time
And we obtain:
One more time, we take the positive time:
Finally: