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slavikrds [6]
3 years ago
8

How are changes in energy and matter related

Physics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

According to Einstein's famous equation, matter can convert into energy (and viceversa) as follows:

E=mc^2

where

E is the energy

m is the mass

c is the speed of light (3\cdot 10^8 m/s)

Given the huge value of c^2, we see that even a tiny amount of matter is able to release a huge amount of energy, when the whole mass is converted into energy. This is precisely what happens in nuclear reactions. For example, in the process of nuclear fusion (that occurs in the core of the stars), two light nuclei fuse together into a heavier nucleus. The mass of the final nucleus is lower than the total mass of the initial nuclei, so part of the mass has been converted into energy according to the equation above: this is why the amount of energy produced by stars is so big.

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What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect t
Helen [10]

Missing details: figure of the problem is attached.

We can solve the exercise by using Poiseuille's law. It says that, for a fluid in laminar flow inside a closed pipe,

\Delta P =  \frac{8 \mu L Q}{\pi r^4}

where:

\Delta P is the pressure difference between the two ends

\mu is viscosity of the fluid

L is the length of the pipe

Q=Av is the volumetric flow rate, with A=\pi r^2 being the section of the tube and v the velocity of the fluid

r is the radius of the pipe.

We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:

\mu=0.001 Pa/s is the dynamic water viscosity at 20^{\circ}

L=4.0 cm=0.04 m

Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s

and r=1 mm=0.001 m

Using these data in the formula, we get:

\Delta P = 3200 Pa

However, this is the pressure difference between point P and the end of the needle. But the end of the needle is at atmosphere pressure, and therefore the gauge pressure (which has zero-reference against atmosphere pressure) at point P is exactly 3200 Pa.

8 0
3 years ago
Two trumpet players are trying to tune their instruments. When they are in tune, they will both be playing the same note and no
marusya05 [52]

Answer:

The second trumpeter will be playing at frequency = 515 Hz

Explanation: Given that the note sounds lower and they can hear 20 beats in 4.0 s. 

Beat frequency = 20/4 = 5 Hz

Beat frequency = F2 - F1

5 = 520 - F1

F1 = 520 - 5

F1 = 515 Hz

Since the note sound lower, the second trumpeter will be playing at 515 Hz frequency

8 0
3 years ago
Question #4
IrinaVladis [17]
2) transverse



hope this helped:)
3 0
3 years ago
Read 2 more answers
Two technicians are discussing fuse testing. Technician A says that a test light should light on both test points of the fuse if
Murljashka [212]

Answer:

C. Both technicians A and B

Explanation:

Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.

4 0
3 years ago
Which of these are broken down during chemical, but not physical, changes?
Doss [256]

I think your answer is D

because you already said its not a B is a liquid and  not a solid so its harder to have a chemical change C is solutions and D is compound and I know for a fact that a compound is a solid and if C is also a solid then that could also be a possible answer choice.

5 0
3 years ago
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