<span>C. switching to cheaper fuel. Physical capital pertains to non-human asset. Under this type were the asset that use to process goods and services like machinery, buildings etc.</span>
Get a pull chord light switch installed in her bathroom by a qualified electrician asap. Meanwhile, keep hands as dry as possible, and try not to go near that switch until it's either been properly earthed, or whatever the problem actually is, and get qualified advice on what the problem is. Don't have wet feet either, and don't stand in puddles of water whilst operating - i she has to - the switch. 250V AC mains can be lethal, and at least painful.
Answer: a) The rate constant, k, for this reaction is
b) No
does not depend on concentration.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Given: Order with respect to
= 1
Thus rate law is:
a) ![Rate=k[A]^1](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5E1)
k= rate constant
![0.00250=k[0.484]^1](https://tex.z-dn.net/?f=0.00250%3Dk%5B0.484%5D%5E1)

The rate constant, k, for this reaction is
b) Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
Half life is the amount of time taken by a radioactive material to decay to half of its original value.


Thus
does not depend on concentration.
Answer:

Explanation:
As we know that the sixth order maximum will have path difference given as

here we know that
N = order of maximum

now we have

so we know that


Answer:
It does not represent a physical change