<u>D.</u>
For every action ther is an equal and opposite reaction.
equal in force, opposite in direction
I=22 ÷20
Explanation:
then put the on the calculator you'll get you answer
Answer:
a)
b)
Explanation:
a)
Using the conservation of energy between the moment when the bullet hit the block and the maximum compression of the spring.
![\frac{1}{2}MV^{2}=\frac{1}{2}k\Delta x^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DMV%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7Dk%5CDelta%20x%5E%7B2%7D)
Where:
- M is the bullet-block mass (0.00535 kg + 2.174 kg = 2.17935 kg)
- V is the speed of the system
- k is the spring constant (6.17*10² N/m)
- Δx is the compression of the spring (0.0634 m)
Then, let's find the initial speed of the bullet-block system.
![V^{2}=\frac{k\Delta x^{2}}{M}](https://tex.z-dn.net/?f=V%5E%7B2%7D%3D%5Cfrac%7Bk%5CDelta%20x%5E%7B2%7D%7D%7BM%7D)
![V=\sqrt{\frac{6.17*10^{2}*0.0634^{2}}{2.17935}}](https://tex.z-dn.net/?f=V%3D%5Csqrt%7B%5Cfrac%7B6.17%2A10%5E%7B2%7D%2A0.0634%5E%7B2%7D%7D%7B2.17935%7D%7D)
b)
Using the conservation of momentum we can find the velocity of the bullet.
![mv=MV](https://tex.z-dn.net/?f=mv%3DMV)
![v=\frac{MV}{m}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7BMV%7D%7Bm%7D)
![v=\frac{2.17935*1.067}{0.00535}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2.17935%2A1.067%7D%7B0.00535%7D)
I hope it helps you!
Just search it up on google for the correct answer, not that hard.
Explanation:
The answer that would best complete the given statement above would be option B. When describing how power and work are similar you would want to mention that <span>you must know force in order determine both work and power. Hope this answers your question. Have a great day!</span>