I believe the answer is A
Answer:
A) Motion-sensor activated cameras
Explanation:
Motion sensor activated cameras are the ones which actuate a trigger when any sort of motion is detected by them. They can play alarming sound, send e-mails and zoom the frame of motion as a response to the detected motion.
Motion sensor cameras can be of two types:
1. Fixed view camera
2. Rotating view camera
Fixed view cameras are in fixed position and they always point in the same direction for the view while the rotating cameras are the ones which can change their direction of view.
For a small and high security space we can use the fixed type camera so that we do not miss any suspicious movements. For wide areas and distant vision we use rotating cameras.
Answer:
Apparent
The key discovery about Cepheid variable stars that led in the 1920s to the resolution of the question of whether spiral "nebulae" were separate and distant galaxies or part of the Milky Way Galaxy was the direct relationship between the pulsation period and the absolute brightness or luminosity of the Cepheid variables. A measurement of apparent brightness of a variable star could then be used to determine the distance to the "nebula" containing it.
Explanation:
A variable star is a star with changing apparent brightness. The changes can occur over years or in a fraction of seconds. For example the sun whose energy output varies by approximately 0.1 percent of its magnitude, over an 11-year solar cycle. This variable(apparent brightness) can be used to determine how far a variable star is (distance). Therefore, a measurement of apparent brightness of a variable star could then be used to determine the distance to the "nebula" containing it.
Answer:
112m/s
Explanation:
14x8=112 therefore meaning the zebra would run 112m/s
The distance traveled by the student's boxcar that starts from rest and reaches an acceleration and velocity of 13.1 m/s² and 24.5 m/s, respectively, is 22.9 meters.
We can find the distance traveled by the boxcar with the following kinematic equation:
Where:
: is the final velocity = 24.5 m/s
: is the initial velocity = 0 (it starts from rest)
a: is the acceleration = 13.1 m/s²
d: is the distance =?
By solving the above equation for <em>d</em>, we have:
Therefore, the boxcar will travel 22.9 meters.
You can find more about distance and acceleration here: brainly.com/question/14363745?referrer=searchResults
I hope it helps you!