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3 years ago

The leading cause of air pollution is _____. automobiles solar power furnaces cigarette smoke

Chemistry

2 answers:

Naddika [18.5K]3 years ago

8 0

Automobiles have they highest cost for of pollution in the air

Luda [366]3 years ago

6 0

Answer: Option (a) is the correct answer.

Explanation:

The presence of harmful substances in air or environment is known as pollution.

For example, emission of smoke from automobiles releases harmful gases like carbon monoxide into the atmosphere leading to pollution.

Whereas cigarette smoke also causes pollution into the environment but out of the given options automobiles contribute greatly to air pollution.

Thus, we can conclude that the leading cause of air pollution is automobiles.

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9966 [12]

Potassium, aluminum, silicon, magnesium neon

3 0

2 years ago

Na+ and Cl- __________ ___________________________ Na+ and PO4 3- __________ ___________________________ Na+ and SO4 2- ________

bagirrra123 [75]

Answer:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as $Na^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaCl$ .

(2) Sodium is carrying +1 charge called as $Na^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_3PO_4$ .

(3) Sodium is carrying +1 charge called as $Na^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2SO_4$ .

(4) Sodium is carrying +1 charge called as $Na^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2CO_3$ .

(5) Potassium is carrying +1 charge called as $K^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $KCl$ .

(6) Potassium is carrying +1 charge called as $K^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $K_3PO_4$ .

(7) Potassium is carrying +1 charge called as $K^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $K_2SO_4$ .

(8) Potassium is carrying +1 charge called as $K^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $K_2CO_3$ .

(9) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $CaCl_2$ .

(10) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $Ca_3(PO_4)_2$ .

(11) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $CaSO_4$ .

(12) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $CaCO_3$ .

(13) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $NH_4Cl$ .

(14) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $NH_4_3PO_4$ .

(15) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $NH_4_2SO_4$ .

(16) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $NH_4_2CO_3$ .

(17) Iron is carrying +3 charge called as $Fe^{+3}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $FeCl_3$ .

(18) Iron is carrying +3 charge called as $Fe^{+3}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $FePO_4$ .

(19) Iron is carrying +3 charge called as $Fe^{+3}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $Fe_2(SO_4)_3$ .

(20) Iron is carrying +3 charge called as $Fe^{+3}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $Fe_2(CO_3)_3$ .

7 0

3 years ago

The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster is the decomposition at 625°C th

Alona [7]

Answer:

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_2$ = rate of reaction at $T_2$

$K_1$ = rate of reaction at $T_1$

$Ea$ = activation energy of the reaction

R = gas constant = 8.314 J/K mol

$E_a=300 kJ/mol=300,000 J/mol$

$T_2=625^oC=898.15 K,T_1=525^oC=798.15 K$

$\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]$

$\log (\frac{K_2}{K_1})=2.185666$

$K_2=153.344\times K_1$

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

4 0

3 years ago

What do agents such as chemicals, elevated temperatures, ionizing radiation, and viruses have in common?

Leni [432]

Answer:

All of them affect the DNA

Explanation:

Chemicals are compounds that can pass through cell membranes and modificate the DNA, elevated temperatures can denaturalize the cell and therefore damage the DNA, ionizing radiation can pass through cell organelles and reach the nucleus affecting the DNA, and viruses inject its DNA into the genome and modify it.

4 0

3 years ago

What are the pH of these solutions?

Tju [1.3M]

Answer:

The answer to your question is below

Explanation:

a) HCl 0.01 M

pH = -log [0.01]

pH = - (-2)

pH = 2

b) HCl = 0.001 M

pH = -log[0.001]

pH = -(-3)

pH = 3

c) HCl = 0.00001 M

pH = -log[0.00001]

pH = - (-5)

pH = 5

d) Distilled water

pH = 7.0

e) NaOH = 0.00001 M

pOH = -log [0.00001]

pOH = -(-5)

pH = 14 - 5

pH = 9

f) NaOH = 0.001 M

pOH =- log [0.001]

pOH = 3

pH = 14 - 3

pH = 11

g) NaOH = 0.1 M

pOH = -log[0.1]

pOH = 1

pH = 14 - 1

pH = 13

3 0

2 years ago