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Ahat [919]
2 years ago
11

Rate how successful you were at using Active Reading skills by responding to the following statement: As i read, i paid attentio

n to my own understanding and recorded my thoughts and questions.​
Chemistry
1 answer:
Aleksandr-060686 [28]2 years ago
8 0

It is possible to rate your active reading skills either by using a number is a specific rate or by using a word that qualifies your performance.

<h3>What are active reading skills?</h3>

Active reading skills are a set of skills that help you read actively; this means skills to effectively read a text and understand it.

<h3>How to rate your reading skills?</h3>

In this case, you are asked to rate your ability to pay attention to your understanding, thoughts, and questions while reading. To do this you can:

Rate using numbers:

  1. Select a specific scale rating such as 1 to 5 or 1 10.
  2. Analyze honestly if you used this ability while reading the text.
  3. Give yourself a number. For example, if you apply this skill only sometimes while reading you can rate yourself 5 out of 10.

Rate using words:

  1. Select the types of words that you will use, the most common ones are frequency words such as always, sometimes, and never.
  2. Analyze honestly your performance.
  3. Find the word that best fits it.

Learn more about rate in: brainly.com/question/2278897

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3.01 × 1023 molecules H2O
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3079.23 is what you get when you multiply the answers.
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3 years ago
The average lung capacity of a human is 6.0L.
Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

(c) 8.77 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol

(b)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol

(c)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol

8 0
4 years ago
In the molar volume of a gas lab, a student
GREYUIT [131]

Answer:

A

Explanation:

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3 years ago
What type of energy does water gain as it sits in the sun?
shutvik [7]

Answer:

Heat Energy

Explanation:

5 0
3 years ago
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