Question

During a storm, the wind exerts a 150 n force ona window that measures 1.00 m by 0.50 m. the outside air pressure is 101 kpa. what pressure in the pascals, does the wind exert on the window

Answer 1

Pressure = F/A

Where,
F = Force exerted = 150 N
A = Area = 1*0.5 = 0.5 m^2

Therefore,

Pressure exerted by wind on the wind = 150/0.5 = 300 N/m^2

1 N/m^2 = 1 Pa,
Then,
Pressure, P = 300 Pa