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Karo-lina-s [1.5K]
3 years ago
9

In which situation is no work considered to be done by a force?

Physics
1 answer:
andre [41]3 years ago
8 0
If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.
If the angle is 45, then there is still some work involved.
The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90. 
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labwork [276]

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4 0
2 years ago
A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released fr
valina [46]
The  spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is
T=2 t = 2 \cdot 0.100 s = 0.200 s
Which means that the frequency is
f= \frac{1}{T}= \frac{1}{0.200 s}=5 Hz
and the angular frequency is
\omega=2 \pi f = 2 \pi (5 Hz)=31.4 rad/s

In a spring-mass system, the maximum velocity of the object is given by
v_{max} = A \omega
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s
6 0
3 years ago
What is one characteristic of informal writing?
7nadin3 [17]
D. It is personal in style.
8 0
3 years ago
Read 2 more answers
An airplane during departure has a constant acceleration of 3 m / s².
Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

Acceleration = speed/time

3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>

t

3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>

8

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

6 0
2 years ago
ou are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As soo
madam [21]

Till the time car is just adjacent to the bicycle we can say

distance moved by cycle = distance moved by car

Time taken by car to accelerate from rest

t = \frac{v_f - v_i}{a}

t = \frac{49 - 0}{7} = 7 s

Time taken by cycle to accelerate

t = \frac{23 - 0}{15} = 1.53 s

now the distance moved by cycle in time "t"

d = \frac{23 + 0}{2}*1.53 + 23(t - 1.53)

distance moved by car in same time

d = \frac{7t + 0}{2}(t)

now make them equal

3.5t^2 = 17.595 - 35.19 + 23t

3.5 t^2 - 23t + 17.595 = 0

t = 5.68 s

so cycle will move ahead of car for t = 5.68 s

8 0
3 years ago
Read 2 more answers
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