Answer:
When friction hits the floor, the oil bounces back up but then down. Then the oil spreads apart. Like an earthquake. Not really though. And try not to spill oil for the first place.
Hope I helped! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥
 
        
             
        
        
        
The  spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is

Which means that the frequency is

and the angular frequency is

In a spring-mass system, the maximum velocity of the object is given by

where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
 
 
        
        
        
D. It is personal in style.
        
                    
             
        
        
        
Constant acceleration of plane = 3m/s²
a) Speed of the plane after 4s
Acceleration = speed/time
3m/s² = speed/4s
S = 12m/s
The speed of the plane after 4s is 12m/s.
b) Flight point will be termed as the point the plane got initial speed, u, 20m/s
Find speed after 8s, v
a = 3m/s²
from, 
a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>
 t
3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>
 8
24 = v - 20
v = 44m/s
After 8s the plane would've 44m/s speed. 
 
        
             
        
        
        
Till the time car is just adjacent to the bicycle we can say
distance moved by cycle = distance moved by car
Time taken by car to accelerate from rest


Time taken by cycle to accelerate

now the distance moved by cycle in time "t"

distance moved by car in same time

now make them equal



so cycle will move ahead of car for t = 5.68 s