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Ilya [14]
4 years ago
3

Carbon dioxide enters an adiabatic compressor at 100 kPa and 300 K at a rate of 0.5 kg/s and leaves at 600 kPa and 450 K. Neglec

ting kinetic energy changes, determine (a) the volume flow rate of the carbon dioxide at the compressor inlet (b) the power input to the compressor.
Physics
1 answer:
ra1l [238]4 years ago
0 0

Answer:

a)\dot V = 0.28335 m3/s

b)\dot W_{in} = 259.63 kW

Explanation:

part a)

inlet volume of air V1 is given as = \frac{RT_1}{P_1}

putting all value in the above formula

V_1 = = \frac{0.1889 kpa - m3/kg .K * 300 K}{100kPa}

V_1 = 0.5667 m3/kg

we know that  volume of flow rate

\dot V = \dot mV_1

\dot V = 0.5 kg/s *0.5667 m3/kg = 0.28335 m3/s

\dot V = 0.28335 m3/s

part b

we know that total energy remain constant, so we have

E_in - E_out = Change in energy in system

E_in = E_out

therefore

\dot W_{in} + \dot m h_1 =\dot m h_2

\dot W_{in} = \dot m h_2- \dot m h_1

the power input to the compressor is

\dot W_{in} = \dot m c_p (h_2- h_1 )

\dot W_{in} = 0.5*5.1926*(450-350 )

\dot W_{in} = 259.63 kW

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Answer:

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3 years ago
Charge is flowing through a conductor at the rate of 420 C/min. If 742 J. of electrical energy are converted to heat in 30 s., w
Y_Kistochka [10]

Answer:

3.53 V

Explanation:

Electric charge: The is the rate of flow of electric charge along a conductor.

The S.I unit of electric charge is C.

Mathematically it is expressed as,

Q = It ............................ Equation 1

Where Q = electric charge, I = current, t = time.

I = Q/t.......................... Equation 2

From the question, charge flows through the conductor at the rate of 420 C/mim

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Substitute into equation 2

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