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Ilya [14]
3 years ago
3

Carbon dioxide enters an adiabatic compressor at 100 kPa and 300 K at a rate of 0.5 kg/s and leaves at 600 kPa and 450 K. Neglec

ting kinetic energy changes, determine (a) the volume flow rate of the carbon dioxide at the compressor inlet (b) the power input to the compressor.
Physics
1 answer:
ra1l [238]3 years ago
0 0

Answer:

a)\dot V = 0.28335 m3/s

b)\dot W_{in} = 259.63 kW

Explanation:

part a)

inlet volume of air V1 is given as = \frac{RT_1}{P_1}

putting all value in the above formula

V_1 = = \frac{0.1889 kpa - m3/kg .K * 300 K}{100kPa}

V_1 = 0.5667 m3/kg

we know that  volume of flow rate

\dot V = \dot mV_1

\dot V = 0.5 kg/s *0.5667 m3/kg = 0.28335 m3/s

\dot V = 0.28335 m3/s

part b

we know that total energy remain constant, so we have

E_in - E_out = Change in energy in system

E_in = E_out

therefore

\dot W_{in} + \dot m h_1 =\dot m h_2

\dot W_{in} = \dot m h_2- \dot m h_1

the power input to the compressor is

\dot W_{in} = \dot m c_p (h_2- h_1 )

\dot W_{in} = 0.5*5.1926*(450-350 )

\dot W_{in} = 259.63 kW

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An ideal gas Carnot cycle with air in a piston cylinder has a high temperature of 1200 K and a heat rejection at 400 K. During t
lana [24]

Answer:

The specific heat capacity is q_{L}=126.12kJ/kg

The efficiency of the temperature is n_{TH}=0.67

Explanation:

The p-v diagram illustration is in the attachment

T_{H} means high temperature

T_{L} means low temperature

The energy equation :

q_{h} = R* T_{h} in(V_{2}/V_{1})

   =0.287 * 1200 ln(3)

   =0.287*1318.33

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The specific heat capacity:

q_{L}=q_{h}*(T_{L}/T_{H})

q_{L}=378.36 * (400/1200)

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The efficiency of the temperature will be:

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2 years ago
A positively charged particle moves through an electric field. As part of a complicated trajectory, the particle passes through
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A load of 1 kW takes a current of 5 A from a 230 V supply. Calculate the power factor.
Pachacha [2.7K]

Answer:

Power factor = 0.87 (Approx)

Explanation:

Given:

Load = 1 Kw = 1000 watt

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