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Kitty [74]
3 years ago
7

Jarin drank a lot of water before going to the doctor. What best describes what would happen to his blood pressure?

Physics
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:Lower

Explanation:

When Jarin drink a lot of water then his blood pressure will be lowers down .

As dehydration causes some of capillary beds to  shut down and it put more pressure on capillaries and arteries causing blood pressure to increase.

sashaice [31]3 years ago
4 0
It lowers your blood pressure for suree 
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If the maximum energy given to an electron during compton scattering is 30 kev, what is the wavelength of the incident photon?
hammer [34]

The wavelength of the incident photon is 1.19x10^{-2} nm.

What is wavelength?

The wavelength, or the distance over which the shape of a periodic wave repeats, is the spatial period in physics. It is a property of both traveling waves and standing waves, as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two neighboring crests, troughs, or zero crossings. The Greek letter lambda is frequently used to denote wavelength. The term wavelength is also sometimes used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

The relationship between wavelength and frequency is inverse, assuming a sinusoidal wave flowing at a constant speed.

Calculations:

The energy loss Δλ=h/m_{e} c(1-cos∅)

Conservation of momentum gives,

h_{f} =P_{e} c-hf'\\hf+hf'=P_{e} c\\hf+hf'=\sqrt{(m_{e} c^{2} } +k^{2} )-me^{2} c^{4} \\\\=\sqrt {(511+30)^{2} -(511)^{2} } \\=178keV

hf=hf'+k=hf-hf'=30keV\\

2hf=178+30\\2hf=208\\hf=104keV\\

Wavelength(λ)=\frac{hc}{104keV}=\frac{1.24keV.nm}{104keV}

Wavelength(λ)=1.19x10^{-2} nm

To learn more about wavelength , visit:

brainly.com/question/12924624

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6 0
2 years ago
. A newly discovered planet has three times the mass and five times the radius of Earth. What is the ratio of the acceleration d
NikAS [45]

Answer:

0.12

Explanation:

The acceleration due to gravity of a planet with mass M and radius R is given as:

g = (G*M) / R²

Where G is gravitational constant.

The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg

The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m

Therefore:

g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²

g(planet) = 1.18 m/s²

Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:

g(planet)/g(earth) = 1.18/9.8 = 0.12

3 0
3 years ago
Two loudspeakers face each other, vibrate in phase, and produce identical 406 Hz tones. A listener walks from one speaker toward
Pavlova-9 [17]

Answer:

1.21 m/s

Explanation:

Given :

2 loudspeakers

F2 - F1 = 2.86 Hz

Speed of sound, V = 343

Fo = frequency when listener is at rest = 406Hz

To obtain the walking speed Vo, speed as observer moves away from speaker ;

Vo = [(F2 - F1) * V] ÷ 2 * Fo

Vo = [2.86 * 343] ÷ (2 * 406)

Vo = 980.98 / 812

Vo = 1.2081034

Vo = 1.21 m/s

3 0
3 years ago
Why can't speed ratio ever equal mechanical advantage?
OLga [1]
Efficiency of a simple machine is the ratio of mechanical advantage and speed ratio.

If mechanical advantage = speed ratio then efficiency = 1
Which is impossible for a practical machine due to presence of frictional force which wastes some energy and thus lowers the output
6 0
3 years ago
Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t
scoundrel [369]

Answer: The correct answer is option (D).

Explanation:

Vertical distance  of first water jet = y_1=50 cm

Vertical distance of second water jet = y_2=100 cm

Horizontal velocity of first water jet =u_y_ 1=1 m/s

Horizontal velocity of second water jet = u_y_2=0.5 m/s

Vertical distance of first water jet:

y_1=(u_y_1)t_1+\frac{1}{2}gt_1^2

u_y_1=0,(u_y_1)t_1=0

t_1=\sqrt{\frac{2y_1}{g}}...(1)

Similarly, Vertical distance of second water jet:

y_2=(u_y_2)t_2+\frac{1}{2}gt_2^2

u_y_2=0,(u_y_2)t_2=0

t_2=\sqrt{\frac{2y_2}{g}}...(2)

Horizontal distance of first water jet:

x_1=(u_x_1)t_1+\frac{1}{2}at_1^2

There is no acceleration in horizontal direction.

a=0,at_1^2=0

x_1=(u_y_1)t_1...(3)

Horizontal distance of second water jet:

x_2=(u_x_2)t_2+\frac{1}{2}at_2^2

a=0,at_2^2=0

x_2=(u_x_2)t_2...(4)

On dividing (3) and (4):

\frac{x_1}{x_2}=\frac{(u_y_1)t_1}{(u_y_2)t_2}

\frac{x_1}{x_2}=\frac{u_y_1}{u_y_2}\times\frac{\sqrt{\frac{2y_1}{g}}}{\sqrt{\frac{2y_2}{g}}}}=\frac{u_y_1}{u_y_2}\sqrt{\frac{y_1}{y_2}}

(from (1) and (2))

\frac{x_1}{x_2}=\frac{1 m/s}{0.5 m/s}\sqrt{\frac{50 cm}{100 cm}}=1.41:1

Hence, the correct answer is option (D).


6 0
4 years ago
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