Answer:
1200N/m
Explanation:
given parameters:
force on the motorcycle spring is 240N
Extension 2cm or 0.02m
unknown _
spring constant:
:?
solution:
to a spring a force applied is given as :
f=ke
f is applied as force
k is spring constant
e is the Extension
240= kx0.02
k=1200N/m
Explanation:
12N by first law of newton is net force after colloision
Answer:
<h2>The pin's final velocity is 5m/s</h2>
Explanation:
Step one:
given data
mass of ball m1=5kg
initial velocity of ball u1=10m/s
mass of pin m2=2kg
initial velocity of pin u2= 0m/s
final velocity of ball v2=8m/s
final velocity of pin v2=?
Step two:
The expression for elastic collision is given as
m1u1+m2u2=m1v1+m2v2
substituting we have
5*10+2*0=5*8+2*v2
50+0=40+2v2
50-40=2v2
10=2v2
divide both sides by 2
v2=10/2
v2=5m/s
The pin's final velocity is 5m/s
B is the answer that I know of.
When it crossed the sternum and is snug around the lap
