here's the first part but for the 2nd one all I know is that the word "compression" goes on the spirals that are closer together.
hope this helps!
This may helpv^2=u^2+2as. v=0 at top of flight. a=acceleration of gravity(vo^2)/2a=s.
I,think potential energy is mgh so 65*100*9,81
Answer:
V = 493421.05 [gal]
Explanation:
This is a problem that consists of handling units, we can calculate by first-hand the volume, then convert units from cubic meters to gallons.
V = 50 * 25 * 1.5
V = 1875 [m^3]
Now we need to convert units, using the proper conversion factor.
![1875[m^3]*\frac{1000lt}{1m^3} *\frac{1gal}{3.8lt} \\493421.05[gal]](https://tex.z-dn.net/?f=1875%5Bm%5E3%5D%2A%5Cfrac%7B1000lt%7D%7B1m%5E3%7D%20%2A%5Cfrac%7B1gal%7D%7B3.8lt%7D%20%5C%5C493421.05%5Bgal%5D)
Answer:
Flight path angle= 15.12°, maximum range= 5.29× 10*6 km
Explanation:
u= 7200m/s, H= 180km= 180000m
Recall that
Maximum height, H= (u*2sin*2∆)/2g
180000= (7200×7200sin*2∆)/2×9.8
(18000×2×98)/7200×7200= sin*2∆
Sin∆= 0.2609
∆= 15.12°
Maximum range, R= u*2/g
(7200×7200)/9.8
= 5289795.92km
= 5.29× 10*6 km