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guapka [62]
3 years ago
6

Find the expression you can substitute for x in 5x+y=10 to solve the system below

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

First you would need to move the variable causing it to change its sign

5x=10-y

Then divide both sides by 5

X=2-1/5y

Then you are left with your answer:

x=2-1/5y

Hope this helps! :3

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Need help anyone know
EleoNora [17]
The answer is D 22 units
7 0
4 years ago
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Find the horizontal asymptote
eimsori [14]

Answer:

Correct answer:  h = 3/5  or y = 3/5

Step-by-step explanation:

Given:

h(x) = (3x² - 9x - 4) / (5x² - 4x + 8)

h = lim x -> ∞ (3x² - 9x - 4) / (5x² - 4x + 8) the numerator and denominator will be divided by x² and get

h = lim x -> ∞ (3 - 9(1/x) - 4 (1/x²)) / (5 - 4(1/x) + 8 (1/x²)

The terms 1/x and 1/x²  when x strives ∞ they strives 0

x -> ∞ ⇒ 1/x -> 0  and x -> ∞ ⇒ 1/x² -> 0

h = (3 - 0 - 0) / (5 - 0 + 0)

Horizontal asymptote is h = 3/5 or y = 3/5

God is with you!!!

5 0
3 years ago
I need some help with this one
k0ka [10]
I believe the answer is 3
8 0
3 years ago
9. Sophia and Lily went to Tacos Galore for lunch. Sophia ordered 3 tacos and 2 burritos and the total of her
Dimas [21]

Answer:

There is no way to know.

Step-by-step explanation:

You need to know how much either burritos cost or how much tacos cost to answer that, let your teacher know.

6 0
3 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
3 years ago
Read 2 more answers
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