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Scrat [10]
3 years ago
15

Do bases gain or lose hydrogen ions

Chemistry
1 answer:
goblinko [34]3 years ago
6 0
It depends upon the situation.
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Consider the following reaction: 2 SO2(g) + O2(g) → 2SO3(g)
matrenka [14]

Answer:

B) -1.00 M/min

Explanation:

Based on the reaction:

2 SO2(g) + O2(g) → 2SO3(g)

<em>2 moles of SO2 are consumed per mole of O2 producing 2 moles SO3</em>

<em />

In the problem, the sulfur dioxide has a rate of change of -2.00M/min. As the moles of oxygen that reacted are half the moles of SO2, its rate of change is halved, that is:

<h3>B) -1.00 M/min </h3>

7 0
3 years ago
The table shows four solutions that were prepared by
Yuliya22 [10]

Answer:

a

Explanation:

7 0
3 years ago
In an experiment, dilute hydrochloric acid reacts with a white solid and bubbles of gas are produced. If this gas is bubbled thr
Andrej [43]

Answer:

Explanation:

Carbon dioxide reacts with calcium hydroxide solution to produce a white precipitate of calcium carbonate. Limewater is a solution of calcium hydroxide. If carbon dioxide is bubbled through limewater, the limewater turns milky or cloudy white.

Hope this helps you

6 0
3 years ago
What is the percent composition of sulfur in H2SO4?
Triss [41]

Answer:

D (32.7%)

Explanation:

4 0
3 years ago
An unknown mass of aluminum requires 6290 joules to raise
Alex Ar [27]

Answer:

124.579 g

Explanation:

Amount of heat required to change the temperature of body is given by the equation given below

Q = m* c * ΔT ____________________equation A

where Q is the total heat energy required by the any object

c is the specific heat capacity of the body J/gK

ΔT is the difference of final temperature of the object and initial temperature of the object

______________________________________

Given Q = 6290 joules

c = 0.900 J/gK

To calculate the temperature in kelvin from Celsius

we can use the formula

K = C + 273

initial temperature  = 23.9°C

initial temperature on kelvin scale =  23.9° + 273 = 296.9

Final temperature  = 80°C

initial temperature on kelvin scale =  80° + 273 = 353

ΔT(temperature difference) = 353 - 296.9 = 56.1

___________________________________________

let the mass of of the  aluminum be m g

substituting the value of Q , c, ΔT in equation A we have

Q = m* c * ΔT

=> 6290 = m * 0.900 * 56.1

=> m = 6290/(0.900 * 56.1 )

=> m = 6290/50.49

=> m = 124.579 g

The mass of the  aluminum is 124.579 g

8 0
3 years ago
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