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3 years ago

A) Calculate the pH of a 2.0x10-4 M solution of aniline hydrochoride, C6H5NH3Cl.

Chemistry

2 answers:

igor_vitrenko [27]3 years ago

8 0

Given the concentration of aniline hydrochloride is $2.0 *10^{-4} M$

Aniline hydrochloride is the conjugate acid of aniline a weak base.

pH can be calculated from $pK_{a}$ anilinium ion the conjugate acid of aniline.

alex41 [277]3 years ago

3 0

Answer: pH = 3.69

Explanation:

The pH of a solution of Aniline Hydrochoride can be calculated using the following mathematical expression :

pH = -log [H+]

= -log [2.0x10-4 M]

= 4 - 0.3010

pH of aniline hydrochoride solution = 3.69

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If a particular ore contains 58.6 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp

rjkz [21]

Answer is: mass of the ore is 8.54kg.<span>

</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.

5 0

3 years ago

How many grams of lithium chloride can be produced from 14.3 g of lithium chlorate when it decomposes into lithium chloride and

vampirchik [111]

6.7 grams of lithium chloride will be produced.

<h3><u>Explanation:</u></h3>

Lithium chlorate is LiClO₃ and lithium chloride is LiCl. The reaction is,

2LiClO₃ = 2LiCl +3O₂.

So here, 2 moles of lithium chlorate produces 2 moles of lithium chloride.

Or, one molecule of lithium chlorate will produce one mole of lithium chloride.

Molecular weight of lithium chlorate = $6.9 + 35.5 + 16\times3$ = 90.4.

So, 14.3 grams of lithium chlorate has 0.16 moles of lithium chlorate.

Thereby, moles of lithium chloride produced is 0.16 moles.

Molecular weight of lithium chloride = $6.9+35.5$ = 42.4 grams.

So weight of lithium chloride produced = $42.4 \times 0.16$ = 6.7 grams.

Thus, weight of lithium chloride produced will be 6.7 grams.

3 0

3 years ago

What is/are the principal product(s) formed when excess methylmagnesium iodide reacts with p-hydroxyacetophenone?

Montano1993 [528]

The end product will depend upon

a) the amount of the reagent taken

b) the final treatment of the reaction

If we have just taken methylmagnesium iodide and p-hydroxyacetophenone, then we will get methane and hydroxyl group substituted with MgI in place of hydrogen

Figure 1

However if we have taken excess of methylmagnesium iodide which is Grignard's reagent followed by hydrolysis we will get different product

Figure 2