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Makovka662 [10]
3 years ago
6

A) Calculate the pH of a 2.0x10-4 M solution of aniline hydrochoride, C6H5NH3Cl.

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
8 0

Given the concentration of aniline hydrochloride is 2.0 *10^{-4} M

Aniline hydrochloride is the conjugate acid of aniline a weak base.

pH can be calculated from pK_{a} anilinium ion the conjugate acid of aniline.

alex41 [277]3 years ago
3 0

Answer: pH = 3.69

Explanation:

The pH of a solution of Aniline Hydrochoride can be calculated using the following mathematical expression :

pH = -log [H+]

= -log [2.0x10-4 M]

= 4 - 0.3010

pH of aniline hydrochoride solution = 3.69

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Determine the freezing point of an aqueous solution containing 10.50 g of magnesium bromide in 200.0 g of water.
Rudiy27
For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:

                                ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where: 
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3

Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol

m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg


For the problem, 
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf

Tf = -1.59 celsius
5 0
3 years ago
Explain why BH3 is trigonal planar and NH3 is trigonal pyramidal.
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Explanation:

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What are the differences between simple, compound, and electron microscopes? WILL GET BRAINIEST!
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Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:

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